Two parallel lines are crossed by a transversal. What is the value of k? k = 9 k = 20 k = 60 k = 71
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Answer:
k=60
Step-by-step explanation:
When a pair of parallel lines is crossed by a transversal, it will make 8 angles, pairs of vertical/opposite angles, two pairs of acute angles and two pairs of obtuse angles. All acute angles are congruent as well as all obtuse angles are congruent. Simply we can say that pairs of acute angles and pairs of obtuse angles are congruent.
From the figure attached below (by the name "Pairs of parallel lines crossed by a transversal"), we get the following equations as:
2k+11=131
Solving for k, we get
2k=131-11
2k=120
k=120/2
k=60
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Answer: The system of equations has NO SOLUTION.
Step-by-step explanation:
The equation of the line in Slope-Intercept form is:
Where "m" is the slope and "b" is the y-intercept.
Given the following system of equations:
Write the first equation and solve for "y" in order to express it in Slope-Intercept form:
You can identify that:
Apply the same procedure with the second equation. Then:
You can identify that:
The slopes of both lines are equal, therefore the lines are parallel and the system has NO SOLUTION.
Let <em>X</em> be a random number selected from the interval. Then the probability density for the random variable <em>X</em> is
8 and 10 are the only even integers that fit the given criterion (6 is more than 0.25 away from 6.35), so that we're looking to compute
P(|<em>X</em> - 8| < 0.25) + P(|<em>X</em> - 10| < 0.25)
… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10.25)
… = P(7.75 < <em>X</em> < 8.25) + P(9.75 < <em>X</em> < 10)
(since P(<em>X</em> > 10) = 0)
… = 0.2740 (8.25 - 7.75) + 0.2740 (10 - 9.75)
… = 0.2055