Question

Can someone please help me

Answer 1

Answer:

See below

Step-by-step explanation:

If |x| < |y|   and both are negative the x will be  to the right of y on the number line.  The point x is loser to the zero on the number line. We can illustrate this by supposing x = -3 and y = -6.

|x| = 3 and |y| = 6  and 3 < 6  but -3 on the number line is higher ( to the right) of -6 and closer to the zero.

|-8 1/3| = 8 1/3

|7  2/3|  = 7 2/3

The absolute values of 8 1/3 > than absolute value of 7 2/3.  The point 7 2/3 is closer to the zero on a number line.

The absolute value of F is greater than absolute value of E so E is closer to the zero line than F.