What makes creating business cards difficult?
1 answer:
You might be interested in
Answer:
Here is the Circle class:
public class Circle { // class definition
private int radius; // private data member of type int of class Circle named radius that stores the value of radius
public Circle(int r) { // parameterized constructor of class Circle that takes radius as argument
radius = r; } // sets value of radius as r
public int getRadius() { // accessor method to get the value of radius
return radius; } // returns the current value of radius
public int Diameter() { // method to compute diameter of a circle
return radius * 2; } // multiply radius value by 2 to compute diameter of Circle
public double Area() { // method to compute area of a circle
return Math.PI * Math.pow(radius, 2); } //the formula of area is
π x radius² where value of π is get using Math.PI
public double Circumference() { // // method to compute circumference of a circle
return 2* Math.PI * radius; } } //the formula of circumference is
2 x π x radius where value of π is get using Math.PI
Explanation:
Here is the Main class:
import java.util.Scanner; //to accept input from user
public class Main { //definition of Main class
public static void main(String[] args) { //start of main method
Scanner scanner = new Scanner (System.in); //creates Scanner object to take input from user
System.out.println("Enter radius: "); //prompts user to enter radius
int r = scanner.nextInt(); //reads the value of radius from user
Circle c = new Circle(r); // calls Constructor of Circle passing r as argument to it using the object c of class Circle
if(c.getRadius()<=0){ //calls getRadius method to get current value of radius using objec and checks if this value (input value of r ) is less than or equal to 0
System.out.println("Error!"); } //when above if condition evaluates to true then print this Error! message
else { //if the value of radius is greater than 0
System.out.println("the radius of this Circle is: " +c.getRadius()); //calls getRadius method to return current value of r (input value by user)
System.out.println("the diameter of this Circle is: " + c.Diameter()); //calls Diameter method to compute the diameter of Circle and display the result on output screen
System.out.printf("the circumference of this Circle is: %.2f", c.Circumference()); //calls Circumference method to compute the Circumference of Circle and display the result on output screen
System.out.println(); //prints a line
System.out.printf("the Area of this Circle is: %.2f", c.Area()); } } }
//calls Area method to compute the Area of Circle and display the result on output screen
The program and its output is attached.
Answer:
C code for half()
#include<stdio.h>
void half(float *pv);
int main()
{
float value=5.0; //value is initialized
printf ("Value before half: %4.1f\n", value); // Prints 5.0
half(&value); // the function call takes the address of the variable.
printf("Value after half: %4.1f\n", value); // Prints 2.5
}
void half(float *pv) //In function definition pointer pv will hold the address of variable passed.
{
*pv=*pv/2; //pointer value is accessed through * operator.
}
- This method is called call-by-reference method.
- Here when we call a function, we pass the address of the variable instead of passing the value of the variable.
- The address of “value” is passed from the “half” function within main(), then in called “half” function we store the address in float pointer ‘pv.’ Now inside the half(), we can manipulate the value pointed by pointer ‘pv’. That will reflect in the main().
- Inside half() we write *pv=*pv/2, which means the value of variable pointed by ‘pv’ will be the half of its value, so after returning from half function value of variable “value” inside main will be 2.5.
Output:
Output is given as image.
