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3 years ago

A(n) __________ prevents outsiders from accessing corporate information the user does not want others to see.

Computers and Technology

1 answer:

kobusy [5.1K]3 years ago

4 0

Answer:

Firewall

Explanation:

A Firewall prevents outsiders from accessing corporate information the user does not want others to see. It could be in the form of a hardware or a software.

Most companies use this in order to keep confidential informations from the public. This is very important to prevent unauthorized access which could lead to different types of problems in the long run.

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Gaming related

Blababa [14]

Answer:

yes affects your K/D

Explanation:

winner winner chicken dinner

please mark me please brainliest or mark thanks

5 0

3 years ago

Write a function that receives two numbers, m and n and calculates and displays the sum of the integers from m to n. For example

Evgesh-ka [11]

Answer:

The program to this question as follows:

Program:

//header file

#include <stdio.h> //defining header file

void inc(int m,int n) //defining method inc

{

int sum, i; //declaring variable

sum=m; //holding value of m variable

for(i=++m;i<=n;i++) //loop for calculate number between given range

{

sum=sum+i; //adding value

}

printf("sum of the integer is : %d",sum);//print value

}

int main() //defining method

{

int m,n; //defining integer variable

printf("Enter m value: "); //message

scanf("%d",&m); //input value by user in variable

printf("Enter n value: "); //message

scanf("%d",&n);//input value by user in variable

inc(m,n); //calling method

return 0;

}

Output:

Enter m value: 3

Enter n value: 7

sum of the integer is :25

Explanation:

In the above code, an "inc" function is declared, that accepts integer parameters that are "m and n", inside the method two integer variable "sum and i" is declared, which is used in the loop.

The loop uses the user parameter to count value and uses the sum variable to calculate there sum.
In the main method, two integer variable n and m are declared, which take value from the user end, and at the last, we call the inc method, that prints sum value.

7 0

3 years ago

Please answer questions in complete sentences!

Troyanec [42]

i need help on that too :cc

7 0

2 years ago

A network that has locations in different countries is considered a WAN.<br> a. Trueb. False

fiasKO [112]

Answer:

True.

Explanation:

Wide area network (WAN) can be defined as a telecommunication network that covers a wide range of geographical locations such as countries or regions across the world for the purpose of communication and sharing information and data between different users.

Hence, a network that has locations in different countries is considered a wide area network (WAN).

Generally, wide area network (WAN) makes it possible for various organizations to interconnect with their branch offices, headquarters and other multiple locations across the globe. Wide area network (WAN) usually span over a distance of 50 kilometers.

6 0

4 years ago

Matching parentheses. An math expression may have a number of parentheses like (, ), [, ], { and }. Each openning parenthesis (,

Solnce55 [7]

C++ Code

#include
using namespace std;

bool match(const char exp[],const int s)
{
// declare a character array to perform stack operations
char stack[s];

// declare top and initialize to -1 and flag to 0
int top=-1,i,flag=0;

// visit all characters in the expression string
for(i=0;i {
// if the character is [ or ( or { then push it into stack
if(exp[i]=='[' || exp[i]=='(' || exp[i]=='{')
{
top++;
stack[top]=exp[i];
}
// if the character is ] or ) or } then check conditions
else if(exp[i]==']' || exp[i]==')' || exp[i]=='}')
{
// check stack is empty or not
if(top!=-1)
{
// check all possible failure conditions
if(exp[i]==')' && (stack[top] == '{' || stack[top]=='['))
{
flag = 1;
break;
}
else if(exp[i]==']' && (stack[top] == '{' || stack[top]=='('))
{
flag = 1;
break;
}
else if(exp[i]=='}' && (stack[top] == '(' || stack[top]=='['))
{
flag = 1;
break;
}
top--;
}
else
{
flag=1;
break;
}
}
}
// after visiting all characters of expression string check if stack is not empty and flag is 1. if any one of the condition is true return false. otherwise return true

if(top>=0 || flag==1)
return false;
else
return true;
}

int main()
{

// declare character array to store expression
char exp[10000];
cout<<"Enter an Expression"<
// read expression from user
cin.getline(exp, 10000);
int s=0;

// find the length of the expression string
for(int i=0;exp[i]!='\0';i++)
{
s++;
}

// call the match function
bool status = match(exp,s);

// print the result based on value returned by match() function
if(status == 1)
cout<<"true"< else
cout<<"false"<
}

Sample Input/Output is attached

3 0

2 years ago