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Phoenix [80]
3 years ago
8

1.) IF f(x)=3x-5 and g(x)=x^2, find (fxg)(3)

Mathematics
1 answer:
kodGreya [7K]3 years ago
8 0
Please use * to denote mult. here, not "x."  "x" is your variable and cannnot also be a symbol for mult.

f(x)g(x) = 3x^3 - 5x^2.

Now let x = 3:

(f*g)(3) = 3(3)^3 - 5(3)^2 = 81-45 =  36  (answer)
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What is the probability of rolling a number greater than or equal to 9 with the sum of two dice, given that at least one of the
olga55 [171]
Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
6 0
2 years ago
The length of a rectangle is shown below:
ludmilkaskok [199]

Answer:

C(5,-4), D(-4,-4)

Have a great day :)

Step-by-step explanation:

7 0
3 years ago
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the perimeter of a basketball court is 284 ft. the length is 40 ft longer than the width. find the dimensions of the court.
mrs_skeptik [129]
284=2x+2(x+40)
284=4x+80
204=4x
51=x
dimensions 51 ft by 91ft
7 0
3 years ago
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Please I need help ASAP<br>pls explain your answer ​
USPshnik [31]

Answer:

47.62 cm

Step-by-step explanation:

ABCD is a rhombus. Each side measures 15 cm.

m<A = 60°.

Here are some properties of a rhombus:

Opposite angles of a rhombus are congruent.

m<C = m<A = 60°

m<ADC = m<ABC

The sum of the measures of the interior angles of a quadrilateral is 360°.

The diagonals are perpendicular bisectors of each other.

m<A + m<C + m<ADC + m<ABC = 360°

60° + 60° + 2m<ADC = 360°

2m<ADC = 240°

m<ADC = 120°

Each diagonal of a rhombus bisects a pair of congruent, opposite angles.

m<ADB + m<CDB = m<ADC

m<ADB = m<CDB

m<ADB + m<ADB = 120°

m<ADB = 60°

Triangle ABD had two angles, <A and <ADB, that measure 60°. Therefore, the third angle, <ABD also measures 60°. That makes triangle ABD an equilateral triangle.

Draw segment AT.

T is the midpoint of BD. The segment AT is the perpendicular bisector of segment BD. Triangle ATD is a 30-60-90 triangle.

Using the ratio of the lengths of the sides of a 30-60-90 triangle, we can calculate the length of AT which is the radius of circle A.

TD : AT : AD

1    : √3 :   2

AD = 15 cm

TD = AD/2

AT = √3 × TD

AT = (AD√3)/2

AT = 7.5√3 = 12.99

AQ = 12.99

perimeter = QD + PB + m(arc)PTQ + BC + CD

perimeter = (15 - 12.99) + (15 - 12.99) + 60°/360° × 2π(12.99) + 15 + 15

perimeter = 47.62

Answer: perimeter = 47.62 cm

7 0
2 years ago
2y-3[3-4(y-5)+2(1-3y)]
soldi70 [24.7K]

Answer:

- 75 - 32y

Step-by-step explanation:

2y-3[3-4(y-5)+2(1-3y)]

= 2y - 3(3 - 4y + 20 + 2 - 6y)

= 2y - 3(25 - 10y)

= 2y - 75 - 30y

= - 75 - 32y

Brainliest???

4 0
2 years ago
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