Answer:
you need to devide the 2 numbers well the 2 fractions bc there mixd numbers well bye it was my pluesure to help you
Step-by-step explanation:
The standard form of a parabola is y=ax²+bx+c
use the three given points to find the three unknown constants a, b, and c:
-2=a+b+c............1
-2=4a+2b+c......... 2
-4=9a+3b+c...........3
equation 2 minus equation 1: 3a+b=0..........4
equation 3 minus equation 2: 5a+b=-2.........5
equation 5 minus equation 4: 2a=-2, so a=-1
plug a=-1 in equation 4: -3+b=0, so b=3
Plug a=-1, b=3 in equation 1: -2=-1+3+c, so c=-4
the parabola is y=-x²+3x-4
double check: when x=1, y=-1+3-4=-2
when x=2, y=-4+6-4=-2
when x=3, y=-9+9-4=-4
Yes.
The cotangent function is defined as the ratio between cosine and sine of a given angle, i.e.
Since you can't have zero at the denominator, the cotangent function is not defined when the sine is zero.
Let's look at your option:
, so the cotangent is defined here
, so the cotangent is not defined here
, so the cotangent is defined here
, so the cotangent is defined here
Answer:
4.8
Step-by-step explanation:
![r = \sqrt[3]{108} \\ \\ r = 4.7622031559 \\ \\ r \approx \: 4.8 \:](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%5B3%5D%7B108%7D%20%20%5C%5C%20%20%5C%5C%20r%20%3D%204.7622031559%20%5C%5C%20%20%5C%5C%20r%20%5Capprox%20%5C%3A%204.8%20%5C%3A%20)
A, c, and d
plug in each x in the equation and it should equal the y value
