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bezimeni [28]
3 years ago
15

I need help

Mathematics
2 answers:
Trava [24]3 years ago
5 0
The answer to that question is the sum of the hours he studied for on both days, which will be 1/4 + 3/8.

However, we cannot add fractions with different denominators. In this case, it's 4 and 8.

So if we want to add them, we must make the denominators similar to each other. How to make 4 into 8? We multiply it by 2: 4 x 2 = 8.

BUT when we multiply fractions, we must multiply both the numerator and the denominator by the same number to keep its original value. In this case, if you want to multiply 4 by 2, you must also multiply 1 by 2.

=> SO to make 1/4 into y/8, we will multiply it like this (1 x 2) / (4 x 2) = 2/8

Now we can add the 2 fractions together. 2/8 + 3/8 = (2 + 3)/8 = 5/8. THIS IS YOUR ANSWER.

TL;DR: He studied 5/8 (or 0.625) hour altogether on both days.
mario62 [17]3 years ago
5 0
The answer is 5/8 hours

You just need to sum it up:
\frac{1}{4} + \frac{3}{8} = \frac{1*2}{4*2} + \frac{3}{8}= \frac{2}{8}+ \frac{3}{8}=\frac{2+3}{8}=\frac{5}{8}
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Wewaii [24]

The bat fit diagonally across the bottom of the suitcase.

Solution:

Length of the suitcase = 20.5 inches

Width of the suitcase = 29 inches

Using Pythagorean theorem,

20.5^{2}+29^{2}=d^{2}

420.25+841=d^{2}

1261.25=d^{2}

Taking square root on both sides, we get

35.5 \approx d

Diagonal of the suitcase = 35.5 inch

Length of the base ball bat = 33 inch

35.5 > 33

Since the diagonal of the suitcase is greater than length of the baseball bat,

The bat fit diagonally across the bottom of the suitcase.

8 0
3 years ago
How many times does 63 go into 7
Anna [14]
63 goes into 7, 9 times
8 0
3 years ago
What's the ratio of 600 m to 3 km
alexandr1967 [171]
I hope this helps you

3 0
3 years ago
Read 2 more answers
The base of a triangle is twelvetwelve more than twice its height. if the area of the triangle is 4545 square​ centimeters, find
mr Goodwill [35]
In order to begin we must start off with the formula for the area of a triangle, which is a=1/2b(h) where a is area, b is base, and h is height.

In this scenario, we know that the area is 45cm^2 and the base is 2h+12 (since it is twice it’s height plus twelve). We can plug this into the area equation and then proceed to solve out accordingly.
a=1/2b(h)
45=1/2(2h+12)(h)
90=(2h+12)(h)
90=2h^2 + 12h
0= 2h^2 + 12h - 90

Simplify by dividing the two out.

h^2 + 6h - 45 = 0.

Now plug into the quadratic formula (with a=1, b=6, and c=-45) as shown in the image below.

After plugging the equation in and solving, we come to the idea that h is roughly equal to 4.34. We can now plug this back into the triangle area formula to solve out for b.
a=1/2b(h)
45=1/2(2h + 12)(h)
45=1/2(20.69)(4.34)
45=45.

In conclusion;
The height is ≈ 4.34
The base is ≈ 8.68

Hope this helps :)
6 0
4 years ago
Help!! Answer !!! about to run out of time in test!!
Gemiola [76]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {8}^{2}  +  {6}^{2}

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {36}^{}  +  {64}^{}

\qquad \sf  \dashrightarrow \: h {}^{2}  = 100

\qquad \sf  \dashrightarrow \: h {}^{}  =  \sqrt{100}

\qquad \sf  \dashrightarrow \: h {}^{}  =  {10}

Now, let's find the asked values ~

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{opposite \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{3}{5}   \: or \: 0.6 \: units

For Cos y :

\qquad \sf  \dashrightarrow \:  \cos(y) =  \dfrac{adjcant \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{3}{5}  \: or \: 0.6 \: units

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0
3 years ago
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