√m/3 = 4
To remove the radical sign, square both sides.
(√m/3)² = 4²
m/3 = 16
To remove the denominator of 3, multiply both sides by 3.
3 (m/3) = 3(16)
m = 48
To check: Substitute m by its value.
√m/3 = 4
√48/3 = 4
√16 = 4
4 = 4
Answer: The probability is 1/190 = 0.005
Step-by-step explanation:
The probability of ordering two specific toppings out of 20 is:
For the first selection he can order 2 of them, peperoni or sausage, so the probability for the first selection is 2/20 = 1/10 (the number of correct options divided by the total number of options)
For the second selection we have only one option, because we assume that the other one was selected previously, here we also had a total of 19 toppings because one already was selected, the probability in this selection is 1/19.
The joint probability is equal to the product of those two probabilities:
P = (1/19)*(1/10) = 1/190 = 0.005
Answer: Choice C
Amy is correct because a nonlinear association could increase along the whole data set, while being steeper in some parts than others. The scatterplot could be linear or nonlinear.
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Explanation:
Just because the data points trend upward (as you go from left to right), it does not mean the data is linearly associated.
Consider a parabola that goes uphill, or an exponential curve that does the same. Both are nonlinear. If we have points close to or on these nonlinear curves, then we consider the scatterplot to have nonlinear association.
Also, you could have points randomly scattered about that don't fit either of those two functions, or any elementary math function your teacher has discussed so far, and yet the points could trend upward. If the points are not close to the same straight line, then we don't have linear association.
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In short, if the points all fall on the same line or close to it, then we have linear association. Otherwise, we have nonlinear association of some kind.
Joseph's claim that an increasing trend is not enough evidence to conclude the scatterplot is linear or not.
Answers is C
Step by step solution is attached
