Question

To solve a problem using the equation for Kepler’s third law, Enrico must convert the average distance of Mars from the Sun from meters into astronomical units. How should he make the conversion?

Answer 1

Answer:

Divide the total distance between mars and sun in kilometers by $1.496*10^8$ to convert this distance into AU

Explanation:

It is simple

Let us suppose the distance of Mars from the Sun is measured in kilometers or meters.

Let us understand how my kilometers are there in one astronomical unit.

one astronomical unit is equal to $1.496*10^8$ kilometers

Suppose the distance between Mars and Sun is "X" kilometers

Then, this distance between Mars and Sun in terms of Astronomical unit is equal to

$\frac{X}{1.496*10^8}$ Astronomical unit

Answer 2

Answer:Enrico must multiply the distance of mars from sun (meters) with the $6.6844\times 10^{-12}$ to convert the distance in astronomical units.

Explanation:

1 astronomical unit  = $1.496\times 10^{11} m$

$1m=\frac{1}{1.496\times 10^{11} } AU=6.6844\times 10^{-12} AU$

Let the distance between the sun and Mars be Y( meters)

Distance in AU= $Y\times 6.6844\times 10^{-12} AU$

Enrico must multiply the distance of mars from sun (meters) with the $6.6844\times 10^{-12}$ to convert the distance in astronomical units.