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igomit [66]
3 years ago
9

To solve a problem using the equation for Kepler’s third law, Enrico must convert the average distance of Mars from the Sun from

meters into astronomical units. How should he make the conversion?
Biology
2 answers:
Alik [6]3 years ago
5 0

Answer:

Divide the total distance between mars and sun in kilometers by 1.496*10^8 to convert this distance into AU

Explanation:

It is simple

Let us suppose the distance of Mars from the Sun is measured in kilometers or meters.

Let us understand how my kilometers are there in one astronomical unit.

one astronomical unit is equal to 1.496*10^8 kilometers

Suppose the distance between Mars and Sun is "X" kilometers

Then, this distance between Mars and Sun in terms of Astronomical unit is equal to

\frac{X}{1.496*10^8} Astronomical unit

vovikov84 [41]3 years ago
3 0

Answer:Enrico must multiply the distance of mars from sun (meters) with the 6.6844\times 10^{-12} to convert the distance in astronomical units.

Explanation:

1 astronomical unit  = 1.496\times 10^{11} m

1m=\frac{1}{1.496\times 10^{11} } AU=6.6844\times 10^{-12} AU

Let the distance between the sun and Mars be Y( meters)

Distance in AU= Y\times 6.6844\times 10^{-12} AU

Enrico must multiply the distance of mars from sun (meters) with the 6.6844\times 10^{-12} to convert the distance in astronomical units.

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PREOPERATIVE DIAGNOSIS: Painful L2 vertebral non-traumatic compression fracture. POSTOPERATIVE DIAGNOSIS: Painful L2 vertebral n
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Answer:

Lets add the missing piece of information for clarity

WHAT ARE THE CPT® and ICD-10-CM CODES REPORTED?

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ICD-10-CM code: [b]

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Our Answer for [b] = M48.56XA

Explanation:

FINDINGS PREOPERATIVELY:

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PROCEDURE:

The patient was admitted to the operating theatre and subjected to general endotracheal anesthesia(it is noted in the report as general anesthesia was exercised.) in a supine way. She was then positioned prone on the Jackson table with her back being prepped and draped in the regular sterile routine. Using biplane image magnifiers, the skin incision sites were noted. 0.5% amount of Marcaine with epinephrine was injected. At first on the left side. A Kyphon trocar was flown downward to the upper lateral region of the pedicle, via the pedicle, and to do the vertebral body in the regular routine.(highlights the way of attending to the defect as it percutaneous with the aid of trocars.) The drill was positioned into the vertebral body then the Kyphon bone tamp was appliednext. In a likely way, the actual process was carried out on on the other side. Balloons were inflated in the process, after which it was deflated and removed, with the cement (doughy appearance) was injected to the two positions in the general manner.(This explains the increase size of the area and the positioning of the cement in a kyphoplasty fashion.) It was carried out with care and sequentially to avoid cement extrusions at the end of inspection, it shows a good fill to the vertebral body sides, upwards in the direction of the upper end plate, and over the midline. The bone filling equipment were taken off, and the trocars were taken off too, Pressure was used later on the skin as sutured with 4-0 nylon. Sand-Aids were used and she was moved to recovery in stable situation.

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No observed complications.

BLOOD LOSS:

Little blood loss.

COUNTS:

Sponge and needle counts were absolutely right.

WHAT ARE THE CPT® and ICD-10-CM CODES REPORTED?

CPT® code: [a]

ICD-10-CM code: [b]

Our Answer for [a] = 22514

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