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juin [17]
3 years ago
6

1) solve for the shaded area 8 cm 15 cm 4 cm 30 cm www.analyzematlucom

Mathematics
2 answers:
Lapatulllka [165]3 years ago
8 0
208cm^2

Area of rectangle=length*breath
So we should divide the shaded area into 2 rectangles
And find the area of those two rectangles separately
And at last we should add them

So the final answer is 208cm^2

Hope it helps
And don’t forget to mark as brainliest
love history [14]3 years ago
3 0

Answer:

208 cm²

Step-by-step explanation:

First, you take the area of the whole rectangle, to do this you simply multiply 30 by 15, meaning that the big rectangle’s area is 450 cm².

Then, you take the area of the small rectangle (the unshaded one), to do this, you simply figure out the sides (they end up being 11 cm and 22 cm, you can find this out through subtracting) and to find the area of this rectangle, you multiply 11 by 22, which gives you 242 cm²

Now all that is left to do is to subtract the unshaded area by the whole rectangles area to find the shaded part! This will look like this: 450-242= 208 cm²

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GREYUIT [131]
P a p a party party p q p w party
4 0
3 years ago
a shipping company charges x dollars to ship a package that weighs up to 1 pound and an additional fee based on the additional w
stepan [7]

Let the additional fee , the shipping company charges be $y .

So for 0.75 pounds, since the weight is less then 1 pound, company charge = $2x

For 3 packages with weigh 2.5 pounds, company charge 3* ( x+(2.5-1)*y )

= 3x+4.5y

For package with weighs 4.2 pounds, company charge x+(4.2-1)y = x+3.1y

So the total amount , company charge = 2x +3x +4.5y +x+3.1y

=6x +7.6y

3 0
3 years ago
At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o
bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, P_0=15

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

P(x)=P_0(1+r)^x

now, we can plug values

P(x)=15(1+0.4142)^x

P(x)=15(1.4142)^x

Average rate of change between 2 years and 4 years:

we can use formula

A_1=\frac{P(4)-P(2)}{4-2}

now, we can plug values

A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}

A_1=14.99914

Average rate of change between 4 years and 6 years:

we can use formula

A_2=\frac{P(6)-P(4)}{6-4}

now, we can plug values

A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}

A_2=29.99770

Average rate of change between 6 years and 8 years:

we can use formula

A_3=\frac{P(8)-P(6)}{8-6}

now, we can plug values

A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}

A_3=59.99425

now, we will check each options

option-A:

we can see that

A_3-A_2=30

A_3-A_2=30

So, this is FALSE

option-B:

A_1=\frac{1}{2}A_2

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

A_1=\frac{1}{2}A_2

so, this is FALSE


5 0
3 years ago
Heart failure is due to either natural occurrences (89%) or outside factors (11%). Outside factors are related to induced substa
Firdavs [7]

Answer:

a) 11% probability that the first patient with heart failure that enters the emergency room has the conditions due to outside factors.

b) 0.0871 = 8.71% probability that third patient with heart failure that enters the emergency room is the first one due to outside factors.

c) The mean number of heart failure patients with the condition due to natural causes that enter the emergency room before the first patient with heart failure from outside factors is 9.09.

Step-by-step explanation:

We have these following probabilities:

89% probability that a patient has heart failure due to natural occurrences.

11% probability that a patient has heart failure due to outside factors.

A) What is the probability that the first patient with heart failure that enters the emergency room has the conditions due to outside factors?

We assume that causes of heart failure between individuals are independent, which means that the probabilities are the same for each patient. So:

11% probability that the first patient with heart failure that enters the emergency room has the conditions due to outside factors.

B) What is the probability that third patient with heart failure that enters the emergency room is the first one due to outside factors?

First two due to natural occurrences, each with 89% = 0.89 probability.

Third due to outside factors, with 11% = 0.11 probability. So

0.89*0.89*0.11 = 0.0871

0.0871 = 8.71% probability that third patient with heart failure that enters the emergency room is the first one due to outside factors.

C) What is the mean number of heart failure patients with the condition due to natural causes that enter the emergency room before the first patient with heart failure from outside factors?

11% with outside factors, so the mean number of patients before the first with outside factors is given by

m = 1/0.11 = 9.09

The mean number of heart failure patients with the condition due to natural causes that enter the emergency room before the first patient with heart failure from outside factors is 9.09.

4 0
3 years ago
Someone please help me
Kamila [148]

This is not a function. The input 7 in set A maps to outputs -1 and -3 at the same time in set B, which is why we don't have a function.

For a function to be possible, each input must map to exactly one output only.

4 0
4 years ago
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