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PilotLPTM [1.2K]
3 years ago
7

the temperature of dry ice is -109.5°F this is 184.2°F less than the outside temperature. What is the outside temperature?

Mathematics
1 answer:
AlladinOne [14]3 years ago
4 0

Answer:

<em>74.7°F</em>

Step-by-step explanation:

You need to add 184.2°F to -109.5°F.

184.2°F + (-109.5°F) =

= 184.2°F - 109.5°F

= 74.7°F

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Arada [10]

Answer:

A. No, the student is not right. The central limit theorem says nothing about the histogram of the sample values. It deals only with the distribution of the sample means.

Step-by-step explanation:

No, the student is not right. The central limit theorem says nothing about the histogram of the sample values. It deals only with the distribution of the sample means. The central limit theorem says that if we take a large sample (i.e., a sample of size n > 30) of any distribution with finite mean \mu and standard deviation \sigma, then, the sample average is approximately normally distributed  with mean \mu and variance \sigma^2/n.

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3 years ago
Riya got 10 correct answers and ten incorrect answers. what is her score if each correct answer is awarded with 3 marks and each
Natasha2012 [34]

Answer:

20

Step-by-step explanation:

Riyas score = ( correct answer × mark) + ( incorrect answer × mark lost )

= ( 3× 10) + ( -1 ×10 )

= 30 -10

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5 0
3 years ago
In a bag of m&amp;m's there are 5 brown 6 yellow 4 blue 3 green and 2 orange. What's the probability of getting 3 yellow m&amp;m
olasank [31]
There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:
_{20} C _3=\frac{20!}{3!(20-3)!}=\frac{20!}{3! \times 17!}=\frac{17! \times 18 \times 19 \times 20}{6 \times 17!}=\frac{18 \times 19 \times 20}{6}=3 \times 19 \times 20= \\&#10;=1140

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:
_6 C _3 = \frac{6!}{3!(6-3)!}=\frac{6!}{3! \times 3!}=\frac{3! \times 4 \times 5 \times 6}{3! \times 6}=\frac{4 \times 5 \times 6}{6}=4 \times 5=20

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.
P=&#10;\frac{20}{1140}=\frac{20 \div 20}{1140 \div 20}=\frac{1}{57}

The probability is 1/57.
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3 years ago
.
Ivenika [448]

Answer:

Theoretically, since it has two sides, it's a 50 50, chance. 50%

6 0
3 years ago
Ryan eats 4 chocolate cream cookies per day. If an equation were written to show the total number of cookies Ryan has eaten afte
skad [1K]
B because you already know number of cookies eaten, you dont know if the total was 12 cookies because you dont know how many days so, if you dont know how many days then y would be the number of days... Good Luck
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