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3 years ago

Factor –8x3 – 2x2 – 12x – 3 by grouping. What is the resulting expression?

Mathematics

2 answers:

Goryan [66]3 years ago

7 0

Answer:

The resulting expression is $(4x+1)(-2x^2-3)$

Step-by-step explanation:

Consider the provided expression.

$-8x^3-2x^2-12x-3$

The above expression can be written as:

$(-8x^3-2x^2)+(-12x-3)$

Take out the greatest common factor from each group.

$-2x^2(4x+1)-3(4x+1)$

Further solve the above expression.

$(4x+1)(-2x^2-3)$

Hence, the required expression is

$(4x+1)(-2x^2-3)$

The resulting expression is $(4x+1)(-2x^2-3)$

mote1985 [20]3 years ago

4 0

The answer is (-4x-1)(2x^2+3) when factoring this expression by grouping

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Step-by-step explanation:

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2 years ago

Solve the system of linear equations for x and y.(cos θ)x + (sin θ)y=1(−sin θ)x + (cos θ)y = 0x=y=

lys-0071 [83]

Answer:

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Step-by-step explanation:

The given system of linear equations is:

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$(cos\theta.sin\theta)x+(sin\theta.sin\theta)y=sin\theta\\\Rightarrow (cos\theta.sin\theta)x+(sin^2\theta)y=sin\theta ....... (1)\\\\(-sin\theta.cos\theta)x+(cos\theta.cos\theta)y=0\\\Rightarrow (-sin\theta.cos\theta)x+(cos^2\theta)y=0 ..... (2)$

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$(sin^2\theta)y+(cos^2\theta)y=sin\theta\\\Rightarrow (sin^2\theta+cos^2\theta)y=sin\theta\\\Rightarrow (1)y=sin\theta\\\Rightarrow y = sin\theta$

Using the equation:

$(-sin\theta)x+(cos\theta)y=0$

Putting value of $y$ :

$\Rightarrow (-sin\theta)x+(cos\theta)sin\theta=0\\\Rightarrow (sin\theta)x=(cos\theta)sin\theta\\\Rightarrow x = cos\theta$

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2 years ago

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Step-by-step explanation:

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