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3 years ago

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The length of a rectangle is 1.2 × 10-4 kilometer. the width of the rectangle is 6.25 × 10-5 kilometer.what is the area in squar

e kilometers of this rectangle.

1 answer:

Serhud [2]3 years ago

3 0

We have 1.2 × 10^(-4) x 6.25 × 10^(-5 ) = 7,5 x 10^(-9) = 75 x 10^(-10) square kilometers.

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Step 2 - Fill in the missing number:<br> 2<br> 1 -3 -10 24<br> a<br> a =

Sunny_sXe [5.5K]

Answer:

16

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

**PLEASE HURRY**

QveST [7]

<h2>For this example I am going to use Cape Coral-Fort Myers Florida which was the fastest growing city of 2017. </h2><h2>As of January of 2000, the population of the city was 102,286, and as of January 1 of 2010, the population was 154,305; therefore, I'm going to examine a population growth over a period of 10 years. </h2><h2>I am going to use the standard model for population growth: </h2><h2> </h2><h2>Where: </h2><h2>= time (in years) </h2><h2>= growth rate </h2><h2>= initial population </h2><h2>= population after a time </h2><h2> </h2><h2>Now, I'm going to replace the values in the equation to get : </h2><h2> </h2><h2> </h2><h2> </h2><h2> </h2><h2> </h2><h2> </h2><h2>Finally, I will multiply x by 100% to obtain 4% which the growing rate of Cape Coral-Fort Myers from 2000 to 2010.</h2>

7 0

3 years ago

PLZ ANWSER WERTAY

kolbaska11 [484]

Answer:

-21

Step-by-step explanation:

after -22 there comes-21 so successor of-22 is -21

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3 years ago

Mary wants to make 20 gallons of a 52% acid solution by mixing together a 84% acid solution and a 4% acid solution. How much of

Setler [38]

Answer:

12 gallons 84%
8 gallons 4%

Step-by-step explanation:

I like to use an "X-diagram" to solve mixture problems. On the left side are the constituents of the mix; in the middle is the result of the mix; and on the right side are the differences between the numbers on each diagonal. These differences are the ratio numbers for the mix.

Here, that means the ratio of 84% solution to 4% solution is ...

48 : 32 = 12 : 8

Note that the last two "ratio numbers" were chosen so their sum is 20, hence they represent the number of gallons of the corresponding constituent in the mix. (The sum of the first two ratio numbers is 48+32=80, so to get a sum of 20, we divide each by 4.)

Mary must use ...

12 gallons of 84% acid solution
8 gallons of 4% acid solution

You may note that this solution takes much longer to explain than to do. The math here can all be done without a calculator.

_____

<em>Check</em>

12 × 84% + 8 × 4% = 10.40 = 20 × 52%

_____

<em>Usual Solution</em>

A more conventional approach would be to assign x to the amount of 84% solution needed. Then the number of gallons of acid in the mix is ...

0.84x + 0.04(20 -x) = 0.52(20)

0.80x + 0.8 = 10.4 . . . . simplify

0.80x = 9.6 . . . . . . . . . . subtract 0.8; next, divide by 0.8

x = 9.6/0.8 = 12 . . . . gallons of 84% acid

20-x = 8 . . . . . . . . . . gallons of 4% acid

3 0

3 years ago

What is the square root of -2i?

Studentka2010 [4]

Answer:

1-i and -1+i

Step-by-step explanation:

We are to find the square roots of $z=0-2i$ . First, convert from Cartesian to polar form:

$r=\sqrt{a^2+b^2}\\r=\sqrt{0^2+(-2)^2}\\r=\sqrt{0+4}\\r=\sqrt{4}\\r=2$

$\theta=tan^{-1}(\frac{b}{a})\\ \theta=tan^{-1}(\frac{-2}{0})\\\theta=\frac{3\pi}{2}$

$z=2(\cos\frac{3\pi}{2}+i\sin\frac{3\pi}{2})$

Next, use the formula $\displaystyle \sqrt[n]{r}\biggr[\cis\biggr(\frac{\theta+2\pi k}{n}\biggr)\biggr]$ where $\displaystyle k=0,1,2,...\:,n-1$ to find the square roots:

<u>When k=1</u>

<u /> $\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(1)}{2}\biggr)\biggr]$

$\displaystyle \sqrt{2}\biggr[cis\biggr(\frac{3\pi}{4}+\pi\biggr)\biggr]$

$\sqrt{2}\biggr(cis\frac{7\pi}{4}\biggr)$

$\sqrt{2}(\cos\frac{7\pi}{4}+i\sin\frac{7\pi}{4})\\ \\\sqrt{2}(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i)\\ \\1-i$

<u>When k=0</u>

<u /> $\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(0)}{2}\biggr)\biggr]$

$\sqrt{2}\biggr(cis\frac{3\pi}{4}\biggr)$

$\sqrt{2}(\cos\frac{3\pi}{4}+i\sin\frac{3\pi}{4})\\ \\\sqrt{2}(-\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}i)\\ \\-1+i$

Thus, the square roots of -2i are 1-i and -1+i

4 0

2 years ago