All categories

3 years ago

A cereal mixture contains almond, wheat and corn in the ratio of 3:5:7. What amount of this mixture contains 9 kg of almond?

Mathematics

1 answer:

Mademuasel [1]3 years ago

8 0

Answer:

The quantity of mixture is 45 kg .

Step-by-step explanation:

Given as :

The ratio of almond , wheat , corn in mixture = 3 : 5 : 7

The quantity of almond in mixture = 9 kg

Let The quantity of mixture = x kg

According to question

The quantity of almond in mixture = $\dfrac{quantity of almond}{quantity of almond + quantity of wheat+ quantity of corn}$ × quantity of mixture

Or, 9 kg = $\dfrac{3}{3 + 5 + 7}$ × x

Or, 9 = $\dfrac{3}{15}$ × x

Or, 9 = $\dfrac{1}{5}$ × x

∴ x = 9 × 5

i.e x = 45

So, The quantity of mixture = x = 45 kg

Hence, The quantity of mixture is 45 kg . Answer

You might be interested in

Which system of equations can you use to find the roots of the equation? x3 – 10x = x2 – 6

vivado [14]

$\bf \stackrel{y}{x^3-10x}=\stackrel{y}{x^2-6}\implies \begin{cases} y=x^3-10x\\ y=x^2-6 \end{cases}$

3 0

3 years ago

Read 2 more answers

Need help with 4, thanks!

Veseljchak [2.6K]

Answer:

x=2

Step-by-step explanation:

In order to solve this problem, you need to find the scale factor. This is done through cross multiplying proportions. In this instance, you have to cross multiply x/4 by 3.5/7. When you multiply x and 7, you get 7x. When you multiply 3.5 and 4, you get 14. Simplify by isolating the variable, and you get 2.

7 0

3 years ago

PLEASE HELP!!!

pogonyaev

Step-by-step explanation:

Part A:

Let $m$ be the number of mittens and $s$ be the number of scarves. Then we have the inequalities:

$s+m\leq 30.$ This says Nivyana and Ana cannot make more than 30 scarves

$50s+25m\geq 1000.$ This says that Nivyana and Ana have to earn at least $1000.

Part B:

The graph is attached.

Notice that the graphs of the inequalities are solid lines, this just means that the points on these lines included to the solutions of each inequality.

The darker shaded region and the solid lines bounding it, are the solutions to the inequalities because that's where the values common to both inequalities are found.

Part C:

From the graph we get two possible solutions:

15 scarves & 10 mittens

25 scarves & 5 mittens.

These two points lie on the solid lines that bound the darker shaded region (I picked those points to stress that the lines bounding the dark region are also solutions.)