3 years ago

How can you use operations with decimals to solve real-world problems

1 answer:

5 0

There's money,measurement,the weather,economy, and there are many more real world things you might need for decimals. <span />

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PLEASE HURRY<br> WILL MARK BRAINLIEST

Studentka2010 [4]

Answer:

The answer is D.

y^2 in the front makes it vertical and since 5^2 is also first, it creates the vertices of 0,5 and 0,-5

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3 years ago

Is (3,2) a solution of the system of equations?Explain<br> 2x+y=8<br> -x+3y=4

lesya692 [45]

Answer:

Step-by-step explanation:

2(3)+2=8

6+2=8

-x+3y=4

-(3)+3(2)=4

-3+6=4

3 does not equal 4

7 0

3 years ago

in the table approximately how much gallons does an average household use every day for showers and for the toliet

Mariana [72]

Answer:

238 gallons

Step-by-step explanation:

81 + 60 + 53 + 44 = 238

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3 years ago

Read 2 more answers

It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp

Semmy [17]

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

= $a^{p^2-q^2}$ × $a^{q^2-r^2}$

= $a^{p^2-r^2}$

Simplifying the third term

5( $(a^p+r)^{p-r}$

= 5 $a^{(p+r)(p-r)}$ = 5 $a^{(p^2-r^2)}$

Performing the division, that is

$\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} }$ ← cancel $a^{(p^2-r^2)}$ on numerator/ denominator leaves

= $\frac{1}{5}$

4 0

3 years ago

PLZ HELP FAST!!! WILL MARK THE BRAINLIEST -Which of the following is an equivalent form of the compound inequality −33 > −3x

castortr0y [4]

Answer:

Step-by-step explanation:

Its the same

8 0

3 years ago