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irinina [24]
3 years ago
6

5 1/8*1 1/3 what is the answer

Mathematics
2 answers:
yan [13]3 years ago
8 0
6 5/6 is the answer to the multiplication of the fractions
Nonamiya [84]3 years ago
4 0

Answer:

decimal form: 6.83333333333 or 6.83

fraction form: 6 1/5

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Cory Randle is an MIS manager for an international consulting firm. Cory travels to different European countries where he implem
romanna [79]

Answer: Efficiency metrics

Step-by-step explanation:

From the question, we are informed that Cory Randle tracks the performance of his system by tracking the response time it takes to respond to Twitter posts mentioning the news station, and as the speed and accuracy of content that are posted on numerous websites and social media sites.

The type of metrics that Cory is using to measure his system is efficiency metrics. It should be noted that this is to determine how efficiently a company is using its resources whether the resources are being used well or they're inefficiently used and wasted. The metrics can also be used to determine how effective management is.

4 0
3 years ago
Guyss help plss i need serious answer I'm buriéd with work plss beg :(​
soldi70 [24.7K]

Answer:

solution given:

B.

CE=2×2=4[base side is double to the line of mid point]

AB=15/2=7.5[b is a mid point]

m<AEC=75°[ corresponding angle]

5.

given:

BD=x+1

CE=x+10

we have

2BD=CE

2(x+1)=x+10

2x+2=x+10

2x-x=10-2

x=8

6 0
3 years ago
PLEASE HELPPPPPP EASY
lianna [129]
The answer to your question is D
5 0
2 years ago
Which is the equation of OB?
GrogVix [38]
The answer is b I hope this helps
6 0
3 years ago
Find the work (in ft-lb) required to pump all the water out of a cylinder that has a circular base of radius 7 ft and height 200
Virty [35]

Answer:

<em>work done is equal to 384279168 lb-ft</em>

<em></em>

Step-by-step explanation:

The cylinder has a circular base of 7 ft.

The height of the cylinder is 200 ft

The weight density of water in the cylinder is 62.4 lb/ft^3

First, we find the volume of the water in the cylinder by finding the volume of this cylinder occupied by the water.

The volume of a cylinder is given as \pi r^{2} h

where, r is the radius,

and h is the height of the cylinder.

the volume of the cylinder = 3.142* 7^{2}*200 = <em>30791.6 ft^3</em>

Since the weight density of water is 62.4 lb/ft^3, then, the weight of the water within the cylinder will be...

weight of water = 62.4 x 30791.6 = <em>1921395.84 lb</em>

We know that the whole weight of the water will have to be pumped out over the height of cylindrical container. Also, we know that the work that will be done in moving this weight of water over this height will be the product of the weight of water, and the height over which it is pumped. Therefore...

The work done in pumping the water out of the container will be

==> (weight of water) x (height of cylinder) = 1921395.84 x 200

==> <em>work done is equal to 384279168 lb-ft</em>

7 0
3 years ago
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