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Sav [38]
3 years ago
9

Which values are solutions to the inequailty below ? check all that apply x2 < 25

Mathematics
1 answer:
Musya8 [376]3 years ago
5 0
X2 < 25
x < /25 (square root 25)
x < + or - 5

Hope it helped!
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1 pts
lubasha [3.4K]

Answer: I believe the answer to your question is 4

Step-by-step explanation:

8 0
2 years ago
Write the following inequality in slope-intercept form. –12x – 2y ≥ –42 y ≥ –6x – 21 y ≤ –6x – 21 y ≤ –6x + 21 y ≥ –6x + 21
xxMikexx [17]

Answer:

y ≤ –6x + 21

Step-by-step explanation:

5 0
3 years ago
Julianne earned $296 working at a grocery store last week. She earned $8 per hour. How many hours did Julianne work?
hram777 [196]
37 hours
You divide 296 by 8 and then you get your answer


4 0
3 years ago
Read 2 more answers
PLEASE HELP I WILL GIVE BRAINLEST
Korvikt [17]

Answer:

Angle WZY=31degrees

Step-by-step explanation:

5x+11=8x-1

11+1=8x-5x

12=3x

X=12/3

X=4

Substitute x=4 in 5x+11

5(4)+11=31

6 0
2 years ago
How do I factor out a constant before factoring out a quadratic? <br>Factor completely: 3w^2-3w-90
pantera1 [17]
3w^2-3w-90 =0 \ \ \:3 \\ \\w^2- w-30 =0 \\ \\a=1 , \ b= -1 , c= -30 \\ \\\Delta =b^2-4ac = (-1)^2 -4\cdot1\cdot (-30) =1+120=121 \\ \\w_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{1-\sqrt{121}}{2 }=\frac{ 1-11}{2}=\frac{-10}{2}=-5

w_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{1+\sqrt{121}}{2 }=\frac{ 1+11}{2}=\frac{12}{2}=6 \\ \\ Answer:\\ \\ w^2- w-30 =(x+5)(x-6)
 

3 0
3 years ago
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