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3 years ago

Factorise fully 8x+6

Mathematics

2 answers:

skelet666 [1.2K]3 years ago

7 0

Answer:

2(4x+3)

Step-by-step explanation:

Find a number that multiplies into both 8 and 6.

That number is 2.

We can divide 8x+6 by 2 to factorise it into 2(4x+3)

asambeis [7]3 years ago

6 0

Answer:

Step-by-step explanation:

8x = 2 * 2 * 2 * x

6 = 2* 3

Greatest common factor = 2

8x + 6 = 2*4x + 2*3

= 2*(4x + 3)

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If p is a positive integer, which could be an odd integer?

sdas [7]

$p > 0 \Rightarrow$

$2p+2$ (even)

$p^3-p$ (odd or even)

$p^2 + p$ (even)

$p^2 - p$ (even)

$7p - 3$ (ODD); 7p odd, 7p-3 = (odd)-(odd)=(odd)

3 0

3 years ago

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Write an inequality for the following scenario

Novosadov [1.4K]

Answer:

1st or 3rd i think. hope this helps.

3 0

3 years ago

Please help please these are short answers

atroni [7]

Answer: The answers are given below.

Step-by-step explanation: The calculations are as follows:

(19) Weight of the puppy last week is

$W_\ell=2\dfrac{1}{2}~\textup{lb},$

and weight of the puppy this week is

$W_p=7\dfrac{1}{4}=\dfrac{29}{4}~\textup{lb}.$

Therefore, the weight gained by the puppy is given by

$W_g=W_p-W_\ell=\dfrac{29}{4}-\dfrac{5}{2}=\dfrac{29-10}{4}=\dfrac{19}{4}=4\dfrac{3}{4}~\textup{lb}.$

(20) Time taken in Route 1 = 1 hour 30 minutes.

Time taken in Route 2 = 1 hour 45 minutes.

Time taken in Route 3 = 1 hour 35 minutes.

Time taken in Route 4 = 1 hour 25 minutes.

Since we want to spent the least amount of time on the bus, so we will be taking route 4.

(21) Time taken by Nazia to complete her language arts homework is

$H_\ell=\dfrac{4}{9}~\textup{hr},$

and the time taken by Nazia to complete her Mathematics homework is

$H_m=\dfrac{2}{9}~\textup{hr}.$

Therefore, Nazia takes more time to complete Language Arts homework, by

$H=H_\ell-H_m=\dfrac{4}{9}-\dfrac{2}{9}=\dfrac{2}{9}~\textup{hr}.$

(22) Quantity of Aluminium collected by Maya is

$A_m=\dfrac{4}{20}=0.2~\textup{lb},$

and the quantity of Aluminium collected by her friend Abigail is

$A_a=\dfrac{7}{8}=0.87~\textup{lb}.$

Therefore,

(a) Abigail collected more aluminium

and

(b) Total Aluminium collected by both the girls is

$T=A_m+A_a=\dfrac{4}{20}+\dfrac{7}{8}=\dfrac{8+35}{40}=\dfrac{43}{40}~\textup{lb}.$

(23) Quantity of snow fall last Wednesday is

$S_w=3\dfrac{1}{4}=3.25~\textup{in.},$

and quantity of snowfall on sunday is

$S_s=3\dfrac{4}{5}=3.8~\textup{in.}.$

Therefore, quantity of snowfall was more on Sunday by

$S=S_s-S_w=3\dfrac{4}{5}-3\dfrac{1}{4}=\dfrac{19}{5}-\dfrac{13}{4}=\dfrac{76-65}{20}=\dfrac{11}{20}~\textup{in.}.$

Thus, all the questions are answered.

3 0

3 years ago

Didn't pay attention and now im stuck :/

Kipish [7]

Answer:

A (First One)

Step-by-step explanation:

Side AC Is Congruent By Side DF

Side CB Is Congruent By Side FE

Side AB Is Congruent By Side DE

(There's no angles shown so it can't be the second option.)

The diagram has lines on the sides, if it we're SAS then the triangle would have an angle.

7 0

3 years ago

Read 2 more answers

A group of workers can plant 8 1/4 acres in 5 1/2 days.

Naddika [18.5K]

Answer: 3/2 acre per day

Explanation:

8 1/4 = 33/4

5 1/2 = 11/2

Find the unit rate in acre per day:

(33/4) divide by (11/2)

33/4 x 2/11 = 3/2

6 0

3 years ago