The spinner below is spun. Find the probability,

X = y - 3<br> 2x + y = 12<br> pls hurry i need badly

vfiekz [6]

$\huge \colorbox{yellow}{Question}$

$2x + y = 12$

$\huge \colorbox{yellow}{Answer}$

$x = y - 3 \: (equation \: 1)$

$2x + y = 12 \: (equation \: 2)$

Substituting the value of x in

( equation 2)

$2x + y = 12$

$2(y - 3) + y = 12$

$2y - 6 + y = 12$

$2y + y = 12 + 6$

$3y = 18$

$y = 18 \div 3$

$y = 6$

Now we get y = 6

Substituting the value of y in

( equation 1 )

$x = y - 3$

$x = 6 - 3$

$x = 3$

Now we get x = 3

$\huge \mathsf\red{Final \: Answer}$

5 0

3 years ago

I need help with systems of equations!! Problem 7-74!

Vika [28.1K]

Problem set A: A=6 and B=2

6=AxB^0 [6=6x1]

24=AxB^2= [24=6x2^2]

Problem set B: A=2 and B=4

32=AxB^2 [32=2x4^2]

128=AxB^3 [128=2x4^3]

7 0

2 years ago

A mayoral candidate in a large metropolitan area has hired you to take a poll to determine the proportion of registered voters w

sveticcg [70]

Answer:

The smallest sample size that will produce an interval with these specifications is 601.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

He would like you to report a 95% confidence interval with a margin of error no more than 0.04. What is the smallest sample size that will produce an interval with these specifications?

We have to find n for which M = 0.04.

We dont know the true proportion, so we use $\pi = 0.5$ , which is when the smallest sample size needed will have it's largest value.