Answer:
The probability that 8 mice are required is 0.2428.
Step-by-step explanation:
Given : A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.
To find : What is the probability that 8 mice are required? The probability that that 8 mice are required is nothing ?
Solution :
Applying binomial distribution,
Where, p is the probability of success 
q is the probability of failure q=1-p, 
n is total number of trials n=8
r=3
Substitute the values,
Therefore, the probability that 8 mice are required is 0.2428.
Answer:
16
Step-by-step explanation:
Given that:
Length of two sides of the triangle = 1 and 16 ;
The largest possible whole-number length of the third side would be ;
Recall from triangle inequality theorem; the length of any two sides of a triangle is greater than the third side. Therefore. The largest possible whole number value the third side could have is:
Assume the third side is the largest :
Then, the third side must be less than the sum of the other two sides ;
Third side < (16 + 1)
Third side < 17
Therefore, the closest whole number lesser than the sum of the other two sides is (17 - 1) = 16
Hey there!
63 = 13 + 2P subtract 13 from both sides
50 = 2P divide both sides by 2
25 = P
So the cost of one pass = $25
Hope this helps!
Okay so you take the 12 feet I'm pretty sure you multiply 12 and 30 and then that's one of your answers and then the 12 and a 75 you must put those to together and that's an answer and you subtract your 12 x 30 and you're 12 x 75 and that's how you get your answer I am pretty sure that's how you and that's how you get your answer I am pretty sure that's how you do it
I believe it would be 12/18 so that would be 2/3 and 0.6 in decimal form
