Answer:
a) The arithmetic sequence with common difference 2 that has 8 as the first term.
b) The arithmetic sequence of common difference -5 and first term 15.
Step-by-step explanation:
Let's use for example the arithmetic sequence with common difference 2 that has 8 as the first term. Then the first two terms of this sequence are:
8, and (8+2) = 10 Therefore the second term is 10.
Another arithmetic sequence of common difference -5 and first term 15. The firs two terms of this sequence are:
15, and (15 - 5) = 10. Therefore again a 10 as second term.
Answer:
not sure but this info might help you.
Step-by-step explanation:
the diagonal in the rectangle splits it into two right angled triangles, hence the hypotenuse is the diagonal.
once you find the measurement, we all know that a square has all sides equal and the diagonal splits it into 2 equilateral triangles. so, the side of the square =the diagonal's measurement.
(2·3.5 + 4·3.25 + 2·1.9 + 1·1.2)·(1 - 0.05) = $23.75
Answer:
284cm^2
Step-by-step explanation:
first, we split up the shape into seperate sections that we can easily find the areas of.
i will draw vertical lines in the bottom left and right, leaving me with 2 seperate rectangles and 1 irregular pentagon.
we know that these rectangles are 4x8cm, so we do 4 * 8 which gives us 32.
there are 2 of these, so 32 x 2 = 64cm^2.
now, i chose to seperarte the pentagon into a rectangle and a triangle,
and i found the height and width of the rectangle to be (18 - (4+4)) x (8+7), or 10 x 15.
the area of the rectangle is 150cm^2.
now, for the triangle.
the line through the centre of th shape is 22cm long, but we only want the part in the triangle. luckily, there are mesurements that can help us with this.
8 + 7 = 15.
22 - 15 = 7.
now we know that the height of the triangle is 7 cm.
from earlier, we also know the base, which is 10cm.
7 x 10 = 70cm^2.
now we add all these together:
70 + 150 + 64 = 284cm^2
Answer:
almost 0%
Step-by-step explanation:
Given that for an insurance company with 10000 automobile policy holders, the expected yearly claim per policyholder is $240 with a standard deaviation of 800
using normal approximation, the probability that the total yearly claim exceeds $2.7 million is calculated as follows:
Sea sumatoria de x = SUMX, tenemos que:
![P (SUMX \geq 2700000) = P(\frac{SUMX - 240*10000}{800 *\sqrt{10000} } \geq \frac{2700000 - 240*10000}{800 *\sqrt{10000} })](https://tex.z-dn.net/?f=P%20%28SUMX%20%5Cgeq%202700000%29%20%3D%20P%28%5Cfrac%7BSUMX%20-%20240%2A10000%7D%7B800%20%2A%5Csqrt%7B10000%7D%20%7D%20%5Cgeq%20%5Cfrac%7B2700000%20-%20240%2A10000%7D%7B800%20%2A%5Csqrt%7B10000%7D%20%7D%29)
![= P (z\geq \frac{2700000 - 240*10000}{800 *\sqrt{10000}})](https://tex.z-dn.net/?f=%3D%20P%20%28z%5Cgeq%20%5Cfrac%7B2700000%20-%20240%2A10000%7D%7B800%20%2A%5Csqrt%7B10000%7D%7D%29)
= P (z => 3.75)
= 1 - P ( z < 3.75)
P = 1 - 0.999912
P = 0.000088
Which means that the probability is almost 0%