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3 years ago

If the measure of angle AOB = 2x + 4 and the measure of angle COD = 4x - 10, write an equation for solve for x

Mathematics

2 answers:

rosijanka [135]3 years ago

5 0

Answer:

$x=7$

Step-by-step explanation:

We know that ∠AOB is (2x+4) and ∠COD is (4x-10).

Note that ∠AOB and ∠COD both have one arc mark.

In other words, they are congruent. Therefore, their angle measures are the same.

So, we can set the two equations equal to each other:

$2x+4=4x-10$

Now, we can solve for x. Let's add 10 to both sides. This yields:

$2x+14=4x$

Now, let's subtract 2x from both sides. This yields:

$14=2x$

Finally, divide both sides by 2. Therefore, the value of x is:

$x=7$

And we're done!

poizon [28]3 years ago

3 0

Answer:

2x+4=4x-10

Step-by-step explanation:

AOB and COD are same

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The time it takes a student to walk from the dorm to the chemistry lab follows roughly a Normaldistribution with a mean of 20 mi

creativ13 [48]

Answer:

95.15%

Step-by-step explanation:

We have that the mean (m) is equal to 20, the standard deviation (sd) 3

They ask us for P (x <25)

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6 0

3 years ago

If a vertical line is dropped from the x-axis to the point (12, –9) in the diagram below, what is the value of sec?

dem82 [27]

Answer:

Value of $\sec \theta = \frac{5}{4}$

Step-by-step explanation:

Given: A vertical line is dropped from the x-axis to the point (12, -9) as shown in the diagram below;

To find the value of $\sec \theta$ .

By definition of secants;

$\sec \theta = \frac{1}{\cos \theta}$

Now, first find the cosine of angle $\theta$

As the point (12 , -9) lies in the IV quadrant , where $\cos \theta > 0$

Consider a right angle triangle;

here, Adjacent side = 12 units and Opposite side = -9 units

Using Pythagoras theorem;

$(Hypotenuse side)^2= (12)^2 + (-9)^2 = 144 + 81 = 225$

$Hypotenuse = \sqrt{225} =15 units$

Cosine ratio is defined as in a right angle triangle, the ratio of adjacent side to hypotenuse side.

$\cos \theta = \frac{Adjacent side}{Hypotenuse side}$

then;

$\cos \theta = \frac{12}{15} = \frac{4}{5}$

and

$\sec \theta = \frac{1}{\cos \theta}= \frac{1}{\frac{4}{5}} = \frac{5}{4}$

therefore, the value of $\sec \theta$ is, $\frac{5}{4}$

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ANTONII [103]

Answer:

Step-by-step explanation:

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Step-by-step explanation:

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