probability of you performing first is 1/13
after your team performs there are 12 teams left, so chance of the other team performing next is 1/12
chance of both happening = 1/13 * 1/12 = 1/156
The price was $824.85 before the discount (yesterday)
Answer:
15 cm
Step-by-step explanation:
Circumference of circle= 2πr, where r us the radius of the circle.
Given that the circumference of circle is 60πcm,
60π= 2πr
Divide by 2 on both sides,
15π= πr
Divide by π on both sides,
15= r
Thus, radius of circle= 15cm.
The probability is a ratio of the possible events to the total events. The total is 52 cards, so the denominator is 52. The individual properties of the specific cards are the following:
Any face or number cards is 4/52, because there are 4 cards for each symbol. On the other hand, each symbol like heart, diamond, club or spade would each have a probability of 13/52 (counting numbers 2 to 10, Ace card, and the 3 face cards). Also, there are 26 each of red and black cards. Furthermore, the words 'or' and 'and' are hint words. When you see 'or', you have to add their individual probabilities. If you see the word 'and', you'll have to multiply them. With that said, the solution is as follows:
a.) P = 4/52 + 4/52 + 4/52 = 3/13
b.) P = (13/52 + 13/52 + 4/52)(26/52) = 15/52
c.) P = 13/52
d.) P = 13/52 + 13/52 + 13/52 = 3/4
Answer:
2.28% of tests has scores over 90.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What proportion of tests has scores over 90?
This proportion is 1 subtracted by the pvalue of Z when X = 90. So
has a pvalue of 0.9772.
So 1-0.9772 = 0.0228 = 2.28% of tests has scores over 90.