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Alex17521 [72]
3 years ago
10

What is the answer of 10a2b + ab2 – 10ab + 3a2b + 4ab – 7ab2

Mathematics
2 answers:
levacccp [35]3 years ago
8 0
Combine like terms

10a-10a+3a = 3a
2b+2b + 4b
ab2-10ab+4ab-7ab2 = - 18ab

answer: 3a + 4b + 18ab
sp2606 [1]3 years ago
3 0
10a^2b + ab^2 - 10ab + 3a^2b + 4ab - 7ab^2

Combine like terms:
= 13a^2b - 6ab  - 6ab^2

Take out common factor ab:
= ab(13a - 6  - 6b)
You might be interested in
The whole numbers from 10-12 are paired with their factors explain why this pairing doesnt describe a function
myrzilka [38]

Answer:

As given whole numbers from 10 - 12 are paired with their factors.

factor of ,10=1,2,5,10 → (10,1),(10,2),(10,5)(10,10)

factor of 11=1, 11 → (11,1),(11,11)

factor of 12=1,2,3,4,6,12→ (12,1),(12,2),(12,3),(12,4),(12,6),(12,12)

As we know for an ordered pair to be function Every element in the domain must have a unique image, i.e it can't have more than one image.

→ As element 10, have four images,which are 1,2,5,10 so it can,t be a function.

Similarly element 11 have two images 1,11 so it can't be a function.

Element 12 have six images 1,2,3,4,6,12, so it also can't be written as function.





8 0
3 years ago
Someone please answer this lol xx
Tamiku [17]
The answer is 4 lol
3 0
3 years ago
Middle school math.​
Nonamiya [84]
The last one the reason is 2 is how much weeks so it’d be 2x - 126 cause that’s how much she wants to lose
7 0
2 years ago
Read 2 more answers
The variable x is twice the value of the variable y and the sum of x and y is 42 solve for x and y.
Oksi-84 [34.3K]

Write two equations with the given information:

1) x = 2y ( x is twice the value of y)

2) x + y = 42

Replace x in the second equation with the value of x in the first equation:

2y + y = 42

Simplify:

3y = 42

Divide both sides by 3:

y = 42 / 3

y = 14

Now we have the value for Y, solve for x by replacing y with 14:

x = 2y

x = 2(14)

x = 28

X = 28 and y = 14

4 0
3 years ago
Read 2 more answers
How do u do b??????????
horrorfan [7]

the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.

the input goes to the 1st machine and the output of that goes to the 2nd machine.

a)

if she uses and input of 6 on the 2nd one, the result will be 6² - 6  = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.

b)

clearly we can never get an output  of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.

let's check something, we need a -5 on the 2nd, so

\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

\bf \stackrel{first~machine}{y=\sqrt{\boxed{6}-5}}\implies y=\sqrt{1}\implies y=1 \\\\\\ \stackrel{second~machine}{y = \boxed{1}^2-6}\implies y = 1-6\implies y = -5

5 0
3 years ago
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