Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
Answer:
The dimensions of the herb garden in the scale drawing are 2.4 in. by 6 in
Step-by-step explanation:
we know that
The dimensions of the garden in the actual are 10 ft by 5 ft
The dimensions of the garden on the scale drawing are 12 in. by 6 in
step 1
Find the scale factor
To find the scale factor divide the corresponding side on the scale drawing by the corresponding side in the actual
so

simplify

That means
1.2 inches in the drawing represent 1 foot in the actual
step 2
Find out the dimensions of the herb garden on the scale drawing
we know that
The dimensions of the herb garden in the actual are 2 ft by 5 ft
Multiply by the scale factor
so


therefore
The dimensions of the herb garden in the scale drawing are 2.4 in. by 6 in
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Answer:
Step-by-step explanation:
The function
has a horizontal asymptote which is 
The function
has a horizontal asymptote which is 
The function
has no horizontal asymptote because the numerator has a degree which is higher than the degree of the denominator,
The function
has a horizontal asymptote which is 