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Answer:
B, C and E
Explanation:
B :
White. In Western cultures, white symbolizes purity, elegance, peace, and cleanliness; brides traditionally wear white dresses at their weddings. But in China, Korea, and some other Asian countries, white represents death, mourning, and bad luck, and is traditionally worn at funerals.
C:
Color psychology has a effect for the world's different cultures. Colors evoke various emotions and beliefs, as well as positive and negative connotations. A color may represent happiness and warmth in one culture but is associated with betrayal and jealousy in another.
E:
Blue is one of the most commonly used colors in American marketing, often considered a safe color for a global audience, because it lacks significant negative connotations. Blue is tied to immortality, spirituality, and heaven in Eastern cultures.
Thank You! Please mark me brainliest!
Sorry if I'm wrong.
Correct the data she entered , and the software will adjust the graph -apex
RDO.
RDO uses the lower-level DAO and ODBC for direct access to databases.
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
