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Sav [38]
3 years ago
15

Can someone please clearly explain how to correctly work out Q3? Much appreciated

Mathematics
1 answer:
vfiekz [6]3 years ago
8 0

the equation for this is:

value = 36000*(0.92)^t

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A worm is at the bottom of a 10ft hole. He starts climbing out of the hole, climbing 3 feet in one hour. Then he takes a break f
Korolek [52]

Answer:

6:00pm is the answer

Step-by-step explanation:


7 0
3 years ago
I need help solving this problem. <img src="https://tex.z-dn.net/?f=4x%20cos%20%5E%7B-1%7D%20%282x%2B4%29-%20%5Csqrt%7B3-3%20x%5
Gnesinka [82]
Given:
f(x)=4xcos^{-1}(2x+4)-\sqrt{3-3x^2}

Using
\frac{d}{dx}cos^{-1}(x)=-\frac{1}{\sqrt{1-x^2}}
we derive
\frac{d}{dx}4xcos^{-1}(2x+4)
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}

Similarly, using
\frac{d}{dx}\sqrt{x}=\frac{1}{2\sqrt{x}}
we derive
\frac{d}{dx}(-\sqrt{3-3x^2})
=\frac{3x}{\sqrt{3-3x^2}}

Therefore, the derivative is
f'(x)=\frac{d}{dx}(4xcos^{-1}(2x+4)-\sqrt{3-3x^2})
=4cos^{-1}(2x+4)-\frac{8x}{\sqrt{1-(2x+4)^2}}+\frac{3x}{\sqrt{3-3x^2}}
3 0
3 years ago
Read 2 more answers
Checking for extraneous solutions
jarptica [38.1K]
There is no restriction on the domain because there is a cube root for all real values positive or negative.  So you can solve this as there are no extraneous solutions...

Cube both sides...

2x-4=-8

2x=-4

x=-2

8 0
3 years ago
1/2 (x - 10) = 7 what does x =
Vika [28.1K]
X=24

Work: x-10=14 x=14+10
6 0
3 years ago
Read 2 more answers
How can one fourth x − 3 = one half x + 8 be set up as a system of equations?
Ganezh [65]
1/4x-3=1/2x+8
Then x=20.
5 0
3 years ago
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