Answer:
n = 144 bags
Step-by-step explanation:
Given:-
- English porcelain miniature figurines in total = 12
- 1 figurine is to be placed in a 100-bag box
Find:-
On the average, how many boxes of tea must be pur-chased by a customer to obtain a complete collection consisting of the 12 nautical figurines?
Solution:-
- We will denote a random variable (X) as the number of figurines in (n) number of bags purchased.
- The probability (p) of finding a figurine in a single bag is ( success ):
p = 1 / 12
- The random variable (X) can follow a binomial distribution with parameters n = number of bags purchased, and p = probability of selecting a bag with a figurine.
X ~ B ( n , 1/12 )
- The average number of bag "n" that need to be purchased to find all 12 figurines available:
E ( X ) = 12
n*p = 12
n = 12 / p
n = 12 / ( 1 / 12) = 12^2
n = 144 bags
- A total of average n = 144 bags need to be purchased to find all the 12 figurines.
The teachers plan will raise money is 1.8 times the static graders plan.The teachers plan to raise a dollar is 5/6 times the static graders plan to raise a dollar.More dollars will be raised by the teachers plan compared to the static graders plan.
Step-by-step explanation:
In the question,
Let what the static graders plan to rise to be $x.
Let what the teachers plan to rise to be $ y
You understand that ;
y =210 +x ----------------(this is 210 dollars more than the static graders raise)
y=x+4/5 x -------------------(but only 4/5 as much as the static graders)
Solving the equations to get x and y
210+x=x+4/5x
5(210+x)=5*x+4x
1050+5x=5x+4x
1050=5x+4x-5x
1050=4x
1050/4=4x/4
x=$262.50
y=210+262.50=$472.50
Additionally, for every $60 raised in teachers plan, the static graders raise $50
This means in teachers plan 1$ raised equals 5/6$ raised in static plan
y=5/6x
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Fund raising comparison brainly.com/question/12421531
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Tu tia tenia 21 años de wear despues de 9 años de edad.
Answer:
An outlier is the number that is much smaller or larger than the other numbers.
In this case it is 29 :)
The answer is 2 since both
![\sin(x),\cos(x)\in[0,1]](https://tex.z-dn.net/?f=%5Csin%28x%29%2C%5Ccos%28x%29%5Cin%5B0%2C1%5D)
The maximum value of 
is 1 and the same for cosine. The sum becomes 1 + 1 which evaluates to 2.
Hope this helps.
