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2 years ago

2.26-30 3x+y=6(0,_)(_,0)(3,_)(6,_)(5,_)

Mathematics

1 answer:

bekas [8.4K]2 years ago

7 0

Answer:

Step-by-step explanation:

In ordered pairs (a,b) a is the x value and b is a y value.

if we have 3x+y=6

if x=0, y=6 --> (0,6)

if y=0, x=2 -->(2,0)

if x=3, y=-3--> (3, -3)

if x=6, y= -12 --->(6, -12)

if x=6, y= -9 ---> (5, -9)

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marishachu [46]

Answer:

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Step-by-step explanation:

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So what we should do is first expand. What I did was I did it one step at a time, starting with (2x+5)(2x+5). This gave me $4x^2+20x+25$ . I then continued to do this, until I got $32x^5+400x^4+2000x^3+5000x^2+6250x+3125$ . Then you asked me what this would be subtracted from 1. So, what I did was set it so that it would follow this rule, making it $1-(32x^5+400x^4+2000x^3+5000x^2+6250x+3125)$ .

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3 years ago

2.26-30 3x+y=6(0,_)(_,0)(3,_)(6,_)(5,_) ​​

2.26-30 3x+y=6(0,_)(_,0)(3,_)(6,_)(5,_)