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NISA [10]
3 years ago
10

3x with a 2 as an exponent +8x=35

Mathematics
2 answers:
Alex3 years ago
8 0

Answer:

The roots are {-5, 7/3}.

Step-by-step explanation:

I am assuming you want to solve this for x.

3x^2 + 8x = 35

3x^2 + 8x - 35 = 0        Try factoring by the 'ac' method.

ac = 3 * -35 = - 105.

We need 2 numbers whose product is -105 and whose sum = + 8.

These are  +15 and  - 7, so we write:

3x^2 + 15x - 7x - 35 = 0      Now factor by grouping:

3x(x + 5) -7(x + 5) = 0          (x + 5) is common so:

(3x - 7)(x + 5) = 0

The roots are {-5, 7/3}.

masha68 [24]3 years ago
8 0
It is (-5)(7/3) that’s the answer
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Ryan is X years old. Two times his age plus fifteen equals thirty-seven minus two. ( 2X + 15=37 - 2) Write an equation showing h
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Answer:

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Step-by-step explanation:

1) 2x+15=37-2

2x+15=35

2x=35-15

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2 2

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2)10x-8=9x+8

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Hope this helps ❤

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X<br> x2 = 36<br> What is the positive solution
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8 0
3 years ago
Which of the following statements is false? A. A rectangle is an equiangular quadrilateral. B. Opposite sides of a parallelogram
Darya [45]

Answer:

D.

Step-by-step explanation:

Choices A., B., and C. are always true.

Choice D. is true only for rectangles with congruent sides, which are squares.

Answer: D.

3 0
3 years ago
Let L be a tangent line to the hyperbola x y = 2 at x = 9 . Find the area of the triangle bounded by L and the coordinate axes.
mafiozo [28]

Answer:

A = 4

Step-by-step explanation:

The equation of the slope of the tangent line L is obtained by deriving the equation of the hyperbola:

y = \frac{2}{x}

y'=-2\cdot x^{-2}

The numerical value of the slope is:

y' = -2 \cdot (9)^{-2}\\y' = -\frac{2}{81}

The component of the y-axis is:

y = \frac{2}{9}

Now, the tangent line has the following mathematical model:

y = m \cdot x + b

The value of the intercept is found by isolating it within the equation and replacing all known variables:

b = y - m \cdot x

b = \frac{2}{9}-(-\frac{2}{81} )\cdot (9)\\b = \frac{4}{9}

Thus, the tangent line is:

y = -\frac{2}{81}\cdot x + \frac{4}{9}

The vertical distance between a point of the tangent line and the origin is given by the intercept.

d_{y} = \frac{4}{9}

In order to find horizontal distance between a point of the tangent line and the origin, let equalize y to zero and clear x:

-\frac{2}{81}\cdot x + \frac{4}{9}=0

-\frac{2}{9}\cdot x + 4 = 0

x = 18

d_{x} = 18

The area of the triangle is computed by this formula:

A = \frac{1}{2}\cdot d_{x}\cdot d_{y}

A = \frac{1}{2}\cdot (18)\cdot (\frac{4}{9} )

A = 4

4 0
3 years ago
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