20×1=20
20×2=40
20×3=60
20×4=80
20×5=100
20×6=120
20×7=140
20×8=160
20×9=180
20×10=200
(Only include this if the table is up to 12)
20×11=220
20×12=240
Answer:
x = 1/2y + 1
y = 2x - 2
Step-by-step explanation:
Let's solve for x.
4x−2y=4
Step 1: Add 2y to both sides.
4x−2y+2y=4+2y
4x=2y+4
Step 2: Divide both sides by 4.
4x
4
=
2y+4
4
x=
1
2
y+1
Answer:
x=
1
2
y+1
Let's solve for y.
4x−2y=4
Step 1: Add -4x to both sides.
4x−2y+−4x=4+−4x
−2y=−4x+4
Step 2: Divide both sides by -2.
−2y
−2
=
−4x+4
−2
y=2x−2
Answer:
y=2x−2
Hope this helps!
brainliest?
1. Set up the long addition.
2 4 7
+3 5 8
_______
2. Calculate 7+8, which is 15.
since 15 is two-digit, we carry the first digit 1 to the next column.
1
2 4 7
+ 3 5 8
________
5
3. Calculate 4+5, which is 9. Now add the carry digit of 1, which is 10. Since 10 is two-digit, we carry the first digit 1 to the next column.
1 1
2 4 7
+ 3 5 8
________
0 5
4. Calculate 2+3, which is 5. Now add the carry digit of 1, which is 6.
1 1
2 4 7
+3 5 8
______
6 0 5
5. Therefore, 247 + 358 = 605.
605
Answer:
<em><u>The number of students that like only Nokia </u></em>
<h2>= 30</h2>
Step-by-step explanation:
consider N the number of students who like Nokia → N=?
T the number of students who like Techno → T=35
Statement 1: In a class of 40 students, 5 like neither Nokia nor Techno
we can translate it like this: 35 student like Nokia or Techno
we can note it like this : T∪N= 35
Statement 2: 30 like Techno and Nokia
we can note it : T∩N = 30
using a rule concerning the number of element of a set :
T∪N = N + T - T∩N
then
35 = N + 35 - 30
⇒ N - 30 = 0
⇒ N = 30
The answer is neither.
Let's take an odd number and substitute.
- f(3) = 3³ - 4(3)
- f(3) = 27 - 12
- f(3) = 15 (odd)
Now, let's take an even number.
- f(4) = 4³ - 4(4)
- f(4) = 64 - 16
- f(4) = 48 (even)
Since both even and odd numbers are possible, it is neither.
