2x+.05(2x)
i think this is right let me work it out
Hello,
1)
Let's put some name of vertex:
A with angle A=45°
B with angle B=90°
C The 3 vertex of the triangle of left.
AC=9 , y=AB=BC
With Pythagore, we can say: y²+y²=9²==>2y²=81===>y=9/√2=9√2/2
The other triangle is BDC: cos(60°)=x/y==>x=y*1/2=9√2/4
2)
Let's give some names:
A with angle A=60°
B with angle B=90
C the 3th vertex of the left triangle.
AB=10, BC=y
tan 60°=y/10=sin(60°)/cos(60°)=(√3/2)/(1/2)=√3==>y=10√3
D is the 3 th vertex of the right triangle.
We use Pythagore: y²+y²=x²
x²=2*(10√3)²===>x=10*√6
Answer:
The value of k is -11.
Step-by-step explanation:
Given equation is 3√(x-k)-2=10
Step 1: Since the value of x = 5, we will substitute value of x in the given equation.
3√(5-k)-2=10
=> 3√(5-k) = 10 + 2
=> 3√(5-k) = 12
Step 2: Dividing both sides by 3
3√(5-k)/3 = 12/3
√(5-k) = 4
Step 3 : Squaring both sides
√(5-k)^2 = 4^2
(5-k) = 16
Step 4 : Separating the value of
=> 5-16 = k
=> -11 = k
=> k = -11
Therefore, the value of k is -11.
!!
367 cm sq
You find the area for all the shapes and then add it up
Triangle - 160cm
Square - 144cm
Trapezoid - 63
Answer: A. (72π - 144) mm²
<u>Step-by-step explanation:</u>