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2 years ago

What is 1 and five eights plus 2 and threee sixteenths plus 7 and one half?

Mathematics

2 answers:

Helen [10]2 years ago

8 0

Answer:

11 and 5/16

Hope this answers your question

Finger [1]2 years ago

7 0

Answer:

11 and 5/16

Step-by-step explanation:

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3 years ago

Read 2 more answers

Ursula wrote the sum 5.815 +6.021 as a sum of two mixed numbers. What a sum did she write?

enot [183]

The answer is most likely 9.836

4 0

2 years ago

Choose the constant term that completes the perfect square trinomial. y 2 + 5y

mr Goodwill [35]

each missing number is the square of half the coefficient of the 1st order term
(5/2)² = 25/4

5 0

3 years ago

To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and find

loris [4]

Answer:

Option D - $[0.12$

Step-by-step explanation:

Given : The manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be s=0.16.

To find : The 95% confidence interval for the population standard deviation sigma?

Solution :

Number of sample n=19

The degree of freedom is Df=n-1=19-1=18

The standard deviation of the sample is s=0.16

Applying chi-square table to find critical value,

Upper critical value of $\chi^2$ is $UC=\chi(\frac{0.05}{2},18) = 31.5264$

Lower critical value of $\chi^2$ is

$LC=\chi(1-\frac{0.05}{2},18) = 8.2307$

Lower limit of the 95% confidence interval for the population variance

$L=\frac{(df)\times (s^2)}{UC}$

$L=\frac{18\times (0.16^2)}{31.5264}$

$L=\frac{18\times0.0256}{31.5264}$

$L=\frac{0.4608}{31.5264}$

$L=0.0146$

Upper limit of the 95% confidence interval for the population variance

$U=\frac{(df)\times(s^2)}{LC}$

$U=\frac{18\times (0.16^2)}{8.2307}$

$U=\frac{18\times0.0256}{8.2307}$

$U=\frac{0.4608}{8.2307}$

$U=0.0559$

So, The 95% confidence interval for the population variance is [0.0146, 0.0560]

Now, The 95% confidence interval for the population standard deviation is

$[\sqrt{0.0146}$

$[0.1208$

or $[0.12$

Therefore, Option D is correct.

The 95% confidence interval for the population standard deviation is $[0.12$

6 0

2 years ago

Margot could pickle 500 cucumbers in 2 hours. She got tired and reduced her rate by one half. How long would it take her to pick

Mariulka [41]

Margot could pickle 500 cucumbers in 2 hours.
She got tired and reduced her rate by one half.
=> 250 cucumber in 2 hours
Let's solve how long would it take her to pickle 2000 cucumbers at thenew rate.
=> 2000 / 250 = 8 times 2 hours
=> it will take her 16 hours to do so.

7 0

3 years ago