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2 years ago

What is (5^-2)^3 in standard form? Please answer!

Mathematics

2 answers:

Marina86 [1]2 years ago

8 0

(5^-2)= (1/5^2)... (1/25) now cube that so it will be 1/15625. Hope that helps

neonofarm [45]2 years ago

6 0

Answer:

6.4x10^-5

Step-by-step explanation:

hello, there.

I hope this helps:

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HURRY!!!!!

belka [17]

Answer:

y=10

Step-by-step explanation:

what ever x='s you add 5 and what ever y='s you subtract 5

4 0

2 years ago

Read 2 more answers

Solve the simultaneous<br> equations<br> 2x+y = 3<br> x+y=1

Murrr4er [49]

Answer:

x = 2, y = -1

Step-by-step explanation:

Now change the equation,

→ x + y = 1

→ y = 1 - x

Then the value of x will be,

→ 2x + y = 3

→ 2x + 1 - x = 3

→ x = 3 - 1

→ [ x = 2 ]

Therefore, the value of x is 2.

Now value of y will be,

→ y = 1 - x

→ y = 1 - 2

→ [ y = -1 ]

Hence, the value of y is -1.

8 0

1 year ago

Read 2 more answers

PLEASE HELP ASAP!! Represent the following expressions as a power of the number a where a≠0.

Step2247 [10]

After using the property of power, the expressions as a power of the number a is $(a^3)^{-2} = a^{-6}$ , $(a^{-1}\cdot a^{-2})^{-3} = a^{9}$ and $((a^2)^{-2})^2=a^{-8}$ .

In the given question we have to solve the given expressions as a power of the number a where a≠0.

The first given expression is $(a^3)^{-2}$ .

Using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

Simplifying the expression.

$(a^3)^{-2} = a^{3*(-2)}$

$(a^3)^{-2} = a^{-6}$

The second expression is $(a^{-1}\cdot a^{-2})^{-3}$

Using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

$(a^{-1}\cdot a^{-2})^{-3} = a^{(-1)\times(-3)}\cdot a^{(-2)\times(-3)}$

$(a^{-1}\cdot a^{-2})^{-3} = a^{3}\cdot a^{6}$

Using the property of sum of power $a^m\cdot a^n=a^{m+n}$

$(a^{-1}\cdot a^{-2})^{-3} = a^{(3+6)}$

$(a^{-1}\cdot a^{-2})^{-3} = a^{9}$

The third expression is $((a^2)^{-2})^2$ .

Using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

$((a^2)^{-2})^2=((a^2)^{(-2)\times2})$

$((a^2)^{-2})^2=(a^2)^{-4}$

Again using the property of multiplication of power; $(a^m)^n=a^{mn}$ .

$((a^2)^{-2})^2=a^{2\times(-4)}$

$((a^2)^{-2})^2=a^{-8}$

To learn more about property of power link is here

brainly.com/question/28747844

#SPJ1

7 0

8 months ago

Which point is a solution

Thepotemich [5.8K]

Answer:

what points

Step-by-step explanation:

4 0

2 years ago

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What angle is an x-intercept for the function y=cos (1/2x)

Nastasia [14]

This it goes up by pi

8 0

2 years ago