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Advocard [28]
3 years ago
10

What is (5^-2)^3 in standard form? Please answer!

Mathematics
2 answers:
Marina86 [1]3 years ago
8 0
(5^-2)= (1/5^2)... (1/25) now cube that so it will be 1/15625. Hope that helps
neonofarm [45]3 years ago
6 0

Answer:

6.4x10^-5

Step-by-step explanation:

hello, there.

I hope this helps:

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find two numbers, both smaller than 100, that have common multiple of 450 and highest common factor of 15
Alex_Xolod [135]

Answer:

hello :

90 = 15×6

75 =  15× 5

highest common factor of 90 and is 15 because highest common factor of 5 and 6 is 1

90 = 3² ×2×5

75= 5^3

common multiple of 90 and 75 is : 3²×2×5²  = 450

90 and 75  both smaller than 100.



3 0
4 years ago
(-8,-9) and (3,4) find the slope of the line through the pair of points.
a_sh-v [17]
Slope = (4 + 9)/(3+8) = 13/11

answer
slope = 13/11
3 0
4 years ago
Read 2 more answers
WHICH NUMBER IS LARGER 9.1 OR THE SQUARE ROOT OF 82
kvv77 [185]

Answer: 9.1 is larger

Step-by-step explanation:

9.1 > \sqrt{82}

\sqrt{82} = 9.05

6 0
2 years ago
Read 2 more answers
Gasoline was 2.869 per gallon one week and 2.989 per gallon the next. By how much did the price change
kramer
.12 hope this helps ._.
8 0
3 years ago
In the measurement of the length of a cylinder, the main scale reading of a vernier caliper is 2.8 cm, the vernier reading is 4,
Sloan [31]

Answer:

the reading of the length of the cylinder is 2.84 cm

Step-by-step explanation:

Given the data in the question;

the main scale reading = 2.8 cm

the Vernier reading = 4

the least count of the Vernier = 0.01 cm

the reading of the length of the cylinder = ?

To determine the reading of the length of the cylinder, we simply say;

Reading length = main scale reading + ( Vernier reading × least count )

so we substitute in our given values

Reading length =  2.8 cm + ( 4 × 0.01 cm )

Reading length =  2.8 cm + 0.04 cm

Reading length =  2.84 cm

Therefore,  the reading of the length of the cylinder is 2.84 cm

7 0
3 years ago
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