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zaharov [31]
2 years ago
6

(these are the rest) May i get more help please :( thank you :)

Mathematics
1 answer:
joja [24]2 years ago
3 0

Answer:

7. a = 1,075 sq ft

8. 128 sq ft

9. a = 80 in

10. $28

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Which procedure justifies whether Negative 3 x (5 minus 4) + 3 (x minus 6) is equivalent to Negative 12 x minus 6? The expressio
Nady [450]

Answer:

The expressions are not equivalent because -3(2)(5-4)+3(2-6)=-18 and -12(2)-6=-30

Step-by-step explanation:

Two expressions are said to be equal if after a number is substituted to the expression, they produce the same result (that is they have the same value).

To determine whether -3x(5-4)+3(x-6) is equivalent to -12x-6, we have to substitute the same number to the expression and see if it produces the same result.

Substituting 2 to the first expression gives:

-3×2(5-4) + 3(2 - 6) = -6 - 12 = -18

Substituting 2 to the second expression gives:

-12(2) - 6 = -24 - 6 = -30

Since -3×2(5-4) + 3(2 - 6) = -6 - 12 = -18 and -12(2) - 6 = -24 - 6 = -30, the expressions are not equivalent because they do not produce the same result.

7 0
3 years ago
Read 2 more answers
PLEASE PLEASE HELP
noname [10]

Answer:

8.51x10^{-3}cm

Step-by-step explanation:

In order to add or subtract numbers in scientific notation, the powers of ten must have the same exponent.  In this caes the diameter of an average human body cell is a power of -4 and the diameter of a plant cell is a power of -3.  In order to add them, we can move the decimal over for the body cell diameter:

5.1x10^{-4}=0.51x10^{-3}

Add the two values: 0.51x10^{-3}+8x10^{-3}=8.51x10^{-3}cm

7 0
3 years ago
Read 2 more answers
Given the following geometric sequence, find the common ratio: {3, 18, 108, ...).
vodomira [7]
Geometric sequences go up due to a common ratio. Here the common ratio can be worked out by dividing a term by its previous term e.g term 2 divided by term 1.

18/3 = 6


Therefore the common ratio is 6.
4 0
3 years ago
6-10 divide, another onee thank you!!​
eduard

Answers:

10.) \displaystyle \pm{5}

9.) \displaystyle 1\frac{1}{2}

8.) \displaystyle \pm{1\frac{1}{2}}

7.) \displaystyle \pm{1\frac{1}{2}}

6.) \displaystyle \pm{\frac{1}{2}}

Step-by-step explanations:

10.) \displaystyle \frac{\sqrt{200}}{\sqrt{8}} \hookrightarrow \sqrt{25} \hookrightarrow \frac{\pm{10\sqrt{2}}}{\pm{2\sqrt{2}}} \\ \\ \boxed{\pm{5}}

9.) \displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}

8.) \displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

7.) \displaystyle \frac{\sqrt{63}}{\sqrt{28}} \hookrightarrow \sqrt{2\frac{1}{4}} \hookrightarrow \frac{\pm{3\sqrt{7}}}{\pm{2\sqrt{7}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}

6.) \displaystyle \frac{\sqrt{12}}{\sqrt{48}} \hookrightarrow \sqrt{\frac{1}{4}} \hookrightarrow \frac{\pm{2\sqrt{3}}}{\pm{4\sqrt{3}}} \\ \\ \boxed{\pm{\frac{1}{2}}}

I am joyous to assist you at any time.

5 0
2 years ago
You are selling flowers for a fundraiser . You pay $ 1.50 for each flower plus a flot rate delivery fee of $ 15 . You are sellin
Feliz [49]

Answer:

15÷1 .50=10

Because you are already paying a flat rate of $15. You make 1.50 off of each flower. So you have to sell over 10 flowers to make a profit.

7 0
2 years ago
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