2 apples 3-1=2 because if you have 3 apples and tom takes 1 do the math 1-3 you're answer is 2
Answer:
$1950
Step-by-step explanation:
Simple interest amount payable is given by
A=P(1+rt) where p is principal amount, A is final amount paid, t is time and r is rate of interest. For the first case
A=15000(1+0.03*4)=$16800
For second case
A=15000(1+0.05*5)=$18750
Difference will be 18750-16800=$1950
73,980=70,000+3,000+800+90+0
100=100+00+0
Answer: You need to wait at least 6.4 hours to eat the ribs.
t ≥ 6.4 hours.
Step-by-step explanation:
The initial temperature is 40°F, and it increases by 25% each hour.
This means that during hour 0 the temperature is 40° F
after the first hour, at h = 1h we have an increase of 25%, this means that the new temperature is:
T = 40° F + 0.25*40° F = 1.25*40° F
after another hour we have another increase of 25%, the temperature now is:
T = (1.25*40° F) + 0.25*(1.25*40° F) = (40° F)*(1.25)^2
Now, we can model the temperature at the hour h as:
T(h) = (40°f)*1.25^h
now we want to find the number of hours needed to get the temperature equal to 165°F. which is the minimum temperature that the ribs need to reach in order to be safe to eaten.
So we have:
(40°f)*1.25^h = 165° F
1.25^h = 165/40 = 4.125
h = ln(4.125)/ln(1.25) = 6.4 hours.
then the inequality is:
t ≥ 6.4 hours.
Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:

- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of 660, hence
.
- The standard deviation is of 90, hence
.
- A sample of 100 is taken, hence
.
The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

By the Central Limit Theorem



has a p-value of 0.8665.
1 - 0.8665 = 0.1335.
0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.
To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213