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In-s [12.5K]
3 years ago
14

Solve the equation by completing the square. Round to the nearest hundredth if necessary. x^2+2x=17

Mathematics
1 answer:
Dahasolnce [82]3 years ago
4 0
We have that
x²<span>+2x=17
</span><span>Group terms that contain the same variable
</span>(x²+2x)=17
<span>Complete the square. Remember to balance the equation
</span>(x²+2x+1)=17+1

Rewrite as perfect squares

(x+1)²=18

x+1=(+/-)√18

x=(+/-)√18-1

x1=√18-1----> 3.24

x2=-√18-1----> -5.24


the answer is

the option 

<span>4.) 3.24, –5.24</span>
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I need help its my homework and it's due today<br>Find the base angles.​
MrRa [10]

Answer:

Each base angle would be 70°.

Step-by-step explanation:

<em>*</em><em>Base angles means the two equal angles formed on the base are called base angles.</em>

<em> </em><em>B</em><em>ase means the third unequal side of the triangle.</em><em> </em><em>*</em>

Given triangle is isosceles triangle.

The angle of vertex which is given is <u>40°</u>.

Let each base angle be <em>x</em>.

We know that,

<em>There are two base angles in a isosceles triangle</em>.

And, Sum of angles of triangle is 180° .

Therefore,

\tt \implies \: x + x   + 40 {}^{ \circ}  = 180 {}^\circ

Now Solve For <em>x</em>. That would be the solution.

Steps:

<u>Combine like terms:</u>

\tt \implies2x + 40{}^{ \circ}  = 180{}^{ \circ}

<u>Subtract 40 from both sides:</u>

\tt \implies2x + 40{}^{ \circ}  - 40 = 180{}^{ \circ}   - 40{}^{ \circ}

<u>Simplify </u><u>the</u><u> </u><u>LHS </u><u>and </u><u>RHS</u><u>:</u>

\tt \implies2x + 0 = 140{}^{ \circ}

\tt \implies2x = 140 {}^{ \circ}

<u>Divide both sides by 2:</u>

\tt \implies \cfrac{2x}{2}  =  \cfrac{140{}^{ \circ} }{2{}^{ \circ} }

<u>Use cancellation method and cancel LHS and RHS:</u>

\tt \implies  \cfrac{ \cancel2x}{ \cancel2}  =  \cfrac{ \cancel{140^{ \circ}} }{ \cancel{2{}^{ \circ} }}

\tt \implies \cfrac{1x}{1}  =  \cfrac{70{}^{ \circ} }{1{}^{ \circ} }

\tt \implies{1x}  = {70}^{ \circ}

\tt \implies{x} = 70{}^{ \circ}

Hence, each base angle would be 70°.

<u>Verification</u>:

As we know that sum of angles of triangle is 180°.

So,

\tt \implies \: Base \:  angle + other \:  base \:  angle  + vertex \: angle= 180{}^{ \circ}

We got that one base angles of the given isosceles triangle is 70° and other is 70°, and the vertex angle is 40°[Given].

\tt \implies70{}^{ \circ}  + 70{}^{ \circ}  + 40{}^{ \circ}  = 180{}^{ \circ}

<u>Solve it.</u>

\tt \implies140{}^{ \circ}  + 40{}^{ \circ}  = 180{}^{ \circ}

\tt \implies180{}^{ \circ}   = 180{}^{ \circ}

\tt \: LHS  = RHS

\star \sf \: Hence, Verified.

\rule{225pt}{2pt}

I hope this helps!

Let me know if you have any questions.

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Hello!

When you divide two exponents with the same base you can subtract the exponents

2^5 / 2^3 = 2^2

2^2 = 4

The answer is C) 4

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