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IRISSAK [1]
3 years ago
9

14.955 rounded to the nearest hundredth

Mathematics
2 answers:
sp2606 [1]3 years ago
6 0

Answer:

14.955 to the nearest hundredth is 14.96

Step-by-step explanation:

The hundredths place in this scenario is 5. If you round it up, you get 10, which means that it would turn into 6 since it comes after 5. In conclusion, the answer is 14.96.

diamong [38]3 years ago
6 0
14.955
the 1 in this case is in the TENS place
the 4 is in the ONES place
the 9 is in the TENTHS place
the first 5 is in the HUNDREDTHS place
and the second 5 is in the THOUSANDTHS place
so to round 14.955 to the nearest hundredth you must stop it at the hundredths place (where the first 5 is) but since you are rounding you must look at the number behind it (the second 5 in the thousandths place) to see if you will remain at .95 or round up to .96 since the number behind the hundredths place is a 5 we will then round the whole number up to 14.96 because when the number in the place after the one you are rounding to is 5 or more then you round up if 4 or less u round back down
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Answer:

the previous population was 62,000.

Step-by-step explanation:

The current population of a city = 83,700

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We have to calculate the previous population before increasing 35%.

Let the previous population be p

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3 years ago
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Answer:

The critical value that should be used is T = 2.0796.

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Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

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95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 21 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.0796, which is the critical value that should be used.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.0796\frac{15.49}{\sqrt{22}} = 6.868

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 98.78 - 6.868 = $91.912

The upper end of the interval is the sample mean added to M. So it is 98.78 + 6.868 = $105.648

The 95% confidence interval for the mean repair cost for the dryers is between $91.912 and $105.648.

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3 years ago
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Step-by-step explanation:

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creativ13 [48]

Answer:

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