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alex41 [277]
3 years ago
8

Solve for x. |4x - 5| > 7

Mathematics
2 answers:
trasher [3.6K]3 years ago
8 0

Answer:

x>3

Step-by-step explanation:

|4x-5|>7

4x -5>7

4x >7+5

4x /4>12/4

x >3

solution set={4,5,6,---}

Leto [7]3 years ago
4 0

Answer:

see explanation

Step-by-step explanation:

Inequalities of the type | x | > a have solutions in the form

x < - a OR x > a thus

4x - 5 < - 7 ( add 5 to both sides )

4x < - 2 ( divide both sides by 4 )

x < - \frac{1}{2}

OR

4x - 5 > 7 ( add 5 to both sides )

4x > 12 ( divide both sides by 4 )

x > 3

Solution is x < - \frac{1}{2} or x > 3

This can be expressed in interval notation as

(- ∞, - \frac{1}{2} ) u (3, ∞ )

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Last one lol. Could I have an explanation so I can understand and ty!
grigory [225]

Answer:

(x,y)→(x+7,y)

Step-by-step explanation:

Cuz the point isn't moving up or down so the y is the same and x+7 cuz the point moved 7 units to the right so its position changed in the x-axis.

Im reallyyyy bad at explanations but hope this helped:)

4 0
3 years ago
What is the measurement of x in the equation. 8x+5x+2x-11+6=180
34kurt

Answer:

x = 37/3 = 12.333

Step-by-step explanation:

Step  1  :

Pulling out like terms :

1.1     Pull out like factors :

  15x - 185  =   5 • (3x - 37)

Equation at the end of step  1  :

Step  2  :

Equations which are never true :

2.1      Solve :    5   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation :

2.2      Solve  :    3x-37 = 0

Add  37  to both sides of the equation :

                     3x = 37

Divide both sides of the equation by 3:

                    x = 37/3 = 12.333

4 0
3 years ago
Which of the following can be used as "reasons" in a two-column proof?
Fudgin [204]

Answer:

A definition and a theorem can be used as a reason in a two-column proof. A two column proof is assembled into statement and reason columns, where each statement should have verified reason.

Step-by-step explanation:

3 0
3 years ago
What is the sum? 3k/k^2+k-7/4K
Aleksandr-060686 [28]

Answer:

  \dfrac{k^2+5k}{4k^2}

Step-by-step explanation:

A suitable common denominator is 4k^2. (This eliminates the first and last choices.)

\dfrac{3k}{k^2}+\dfrac{k-7}{4k}=\dfrac{4(3k)}{4(k^2)}+\dfrac{k(k-7)}{k(4k)}\\\\=\dfrac{12k+k^2-7k}{4k^2}=\boxed{\dfrac{k^2+5k}{4k^2}}

3 0
3 years ago
Now please!!!<br> middle school math<br> LOOK AT THE PIC DECIDE FROM THERE
wlad13 [49]
Answer is 0. Use PEMDAS. Trust the process
6 0
3 years ago
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