Max is thinking of a double fact. It has a sum greater than 10 but less than 13. What number fact could it be?

Can someone explain major and minor arcs in relation to circles.

Lelechka [254]

A Major Arc within a circle is something that that is more than half of the circle, and therefore, larger than the minor arc. The way in which this could be used in an example is; Tony has a pizza with 8 slices, 6 of these slices are pepperoni and 2 are chilli beef. In this case, the pepperoni slices are the major arc and the chilli beef slices are the minor arc.
The Major Arc will always be bigger than the minor arc- whether this is 181 degrees to 179, or whether this is 350 degrees to 10 degrees.
The Minor Arc is always the smallest arc, and this can be explained by; Benedict has an apple pie that has 10 slices, between him and his friends, they have eaten four slices. In this case, they have eaten the 'minor arc'
There is a picture attached, and this is the examples of a major and a minor arc.
Hope this has been able to help you :)

3 0

3 years ago

A cube whose edge is 20 cm 1 point

Sav [38]

Answer:

Unpainted surface area = 514.28 cm²

Step-by-step explanation:

Given:

Side of cube = 20 Cm

Radius of circle = 20 / 2 = 10 Cm

Find:

Unpainted surface area

Computation:

Unpainted surface area = Surface area of cube - 6(Area of circle)

Unpainted surface area = 6a² - 6[πr²]

Unpainted surface area = 6[a² - πr²]

Unpainted surface area = 6[20² - π10²]

Unpainted surface area = 6[400 - 314.285714]

Unpainted surface area = 514.28 cm²

6 0

3 years ago

Which figure has the same area as the parallelogram shown below? A. A triangle with a base of 4 mm and a height of 20 mm B. A tr

Arisa [49]

<h2>Answer: A trapezoid with bases of 6 mm and 14 mm and a height of 8 mm </h2>

The parallelogram in the figure has an area of $80mm^{2}$ , according to the following formula, which works for all rectangles and parallelograms:

$A_{parallelogram}=(b)(h)$ (1)

Where $b$ is the base and $h$ is the height

The<u> area of a triangle</u> is given by the following formula:

$A_{triangle}=\frac{1}{2}(b)(h)$ (2)

So, for option A:

$A_{triangle}=\frac{1}{2}(4mm)(20mm)=40mm^{2} \neq 80mm^{2}$

Now, the <u>area of a trapezoid </u>is:

$A_{trapezoid}=\frac{1}{2}(b_{1}+ b_{2})(h)$ (3)

For option B:

$A_{trapezoid}=\frac{1}{2}(15mm+25mm)(2 mm)=40mm^{2} \neq 80mm^{2}$

For option C:

$A_{trapezoid}=\frac{1}{2}(6mm+14mm)(8 mm)=80mm^{2}$ >>>>This is the correct option!

For option D:

$A_{rectangle}=(30mm)(8mm)=240mm^{2} \neq 80mm^{2}$

<h2>Therefore the correct option is C</h2>

5 0

2 years ago

The world's largest pumpkin pie weighed 2020 pounds. The pie was 12 and one-third feet across and one-third foot thick. Write a

Yanka [14]

Answer:

$\frac{1}{3}$ = $\frac{2}{6}$

To find equivalent fractions, multiply be any number that is the same for the numerator/denominator

You can also divide, but it must be divisible by both the numerator/denominator

5 0

3 years ago

L(t) models the length of each day (in minutes) in Manila, Philippines tt days after the spring equinox. Here, t is entered in r

SVETLANKA909090 [29]

Answer:

Given that:

$L(t) = 52\sin(\frac{2 \pi t}{365})+728$

where

L(t) represents the length of each day(in minutes) and t represents the number of days.

Substitute the value of L(t) = 750 minutes we get;

$750= 52\sin(\frac{2 \pi t}{365})+728$

Subtract 728 from both sides we get;

$22= 52\sin(\frac{2 \pi t}{365})$

Divide both sides by 52 we get;

$0.42307692352= \sin(\frac{2 \pi t}{365})$

or

$\frac{2 \pi t}{365} = \sin^{-1} (0.42307692352)$

Simplify:

$\frac{2 \pi t}{365} =0.43683845$

or

$t = \frac{365 \times 0.43683854}{2 \times \pi} = \frac{365 \times 0.43683854}{2 \times 3.14}$

Simplify:

$t \approx 25$ days

Therefore, the first day after the spring equinox that the day length is 750 minutes, is 25 days

4 0

3 years ago

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