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3 years ago

Max is thinking of a double fact. It has a sum greater than 10 but less than 13. What number fact could it be?

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

4 0

The answere would be 11 and 12

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What is the value of x and the length of the segment?

Paha777 [63]

Answer:

x=14

PN=MN=85

Step-by-step explanation:

It is an isosceles triangle because PQ=MQ and QN is perpendicular to PM. PN=MN

8x-27=6x+1

2x=28

x=14

PN=MN=85

4 0

2 years ago

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Express 17.61 as a mixed number in lowest terms

swat32

The number is 17 61/100. 61/100 can't be reduced, because 61 is a prime number.

3 0

3 years ago

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2/0 = 32/48 = 30/0. What number shpuld come in place of the zeros?

Anton [14]

Answer:

$\sf \dfrac{2}{3} = \dfrac{32}{48} = \dfrac{30}{45}$

$\sf \rightarrow \dfrac{2}{x} = \dfrac{32}{48}$

$\sf \rightarrow 2(48)= {32x}$

$\sf \rightarrow 32x= 96$

$\sf \rightarrow x = 3$

<u /> $\rightarrow \sf \dfrac{32}{48} = \dfrac{30}{y}$

$\rightarrow \sf {32y} = 30(48)$

$\rightarrow \sf {32y} = 1440$

$\rightarrow \sf y = 45$

8 0

2 years ago

Please help with corrections

sertanlavr [38]

Answer:

7x12x2=168 I think but how did u do this

5 0

3 years ago

Read 2 more answers

denis-greek [22]

Answer:

Part a) $AB=15\ cm$

Part b) $AB=11.1\ cm$

Part c) $AB=3/5\ cm$

Part d) $AB=3s\ cm$

Step-by-step explanation:

see the attached figure to better understand the question

we know that

To find the length of the image after a dilation, multiply the length of the pre-image by the scale factor

Part a) we have

The scale factor is 5

The length of the pre-image is 3 cm

therefore

The length of the image AB after dilation is

$3(5)=15\ cm$

Part b) we have

The scale factor is 3.7

The length of the pre-image is 3 cm

therefore

The length of the image AB after dilation is

$3(3.7)=11.1\ cm$

Part c) we have

The scale factor is 1/5

The length of the pre-image is 3 cm

therefore

The length of the image AB after dilation is

$3(1/5)=3/5\ cm$

Part d) we have

The scale factor is s

The length of the pre-image is 3 cm

therefore

The length of the image AB after dilation is

$3(s)=3s\ cm$

7 0

3 years ago