I have to turn this in today lol help pls:)

Which number line represents the solution set for inequality 3x<-9 ?

vovikov84 [41]

THE RIGHT ANSWER IS OF THIRD OPTION.

HOPE THIS WILL HELP U...

5 0

2 years ago

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What is the area of this figure? Enter your answer in the box.

astra-53 [7]

The parallelogram is 45 square meters. Multiply the base by the height. The triangle is 36 square meters. Multiply the base by the height and divide by two. Thus, the answer is 81.

3 0

2 years ago

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NOT A SCAM..... PLEASE HELP MEMEEEEEEEEEEEEEE

umka21 [38]

Answer:

(3, 0).

Step-by-step explanation:

dentifying the vertices of the feasible region. Graphing is often a good way to do it, or you can solve the equations pairwise to identify the x- and y-values that are at the limits of the region.

In the attached graph, the solution spaces of the last two constraints are shown in red and blue, and their overlap is shown in purple. Hence the vertices of the feasible region are the vertices of the purple area: (0, 0), (0, 1), (1.5, 1.5), and (3, 0).

The signs of the variables in the contraint function (+ for x, - for y) tell you that to maximize C, you want to make y as small as possible, while making x as large as possible at the same time.

Hence, The Answer is ( 3, 0)

3 0

2 years ago

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There are 9321 leaves on a tree explain why the digit 3 stay the same when

Nat2105 [25]

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

❖ The 3 remains the same when 9,321 is rounded because if you look to the right of the number in the hundreds place, you see 2. 5 and above, give it a shove (round up). 4 and below, leave it alone (round down). Since 2 is below 5, we leave it alone. So 9,321 is rounded to 9,300.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

6 0

3 years ago

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If sinA+cosecA=3 find the value of sin2A+cosec2A

Irina18 [472]

Answer:

$\sin 2A + \csc 2A = 2.122$

Step-by-step explanation:

Let $f(A) = \sin A + \csc A$ , we proceed to transform the expression into an equivalent form of sines and cosines by means of the following trigonometrical identity:

$\csc A = \frac{1}{\sin A}$ (1)

$\sin^{2}A +\cos^{2}A = 1$ (2)

Now we perform the operations: $f(A) = 3$

$\sin A + \csc A = 3$

$\sin A + \frac{1}{\sin A} = 3$

$\sin ^{2}A + 1 = 3\cdot \sin A$

$\sin^{2}A -3\cdot \sin A +1 = 0$ (3)

By the quadratic formula, we find the following solutions:

$\sin A_{1} \approx 2.618$ and $\sin A_{2} \approx 0.382$

Since sine is a bounded function between -1 and 1, the only solution that is mathematically reasonable is:

$\sin A \approx 0.382$

By means of inverse trigonometrical function, we get the value associate of the function in sexagesimal degrees:

$A \approx 22.457^{\circ}$

Then, the values of the cosine associated with that angle is:

$\cos A \approx 0.924$

Now, we have that $f(A) = \sin 2A +\csc2A$ , we proceed to transform the expression into an equivalent form with sines and cosines. The following trignometrical identities are used: