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love history [14]
3 years ago
6

A case of grapefruit weighs 35 3/4 pounds. of this weight, 1/8 is not ripe. What is the weight of the grapefruit that are ripe?

Mathematics
1 answer:
Irina18 [472]3 years ago
3 0
Turn those 2 fractions into a improper fraction and do keep change flip and then turn it back into a mixed number
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igor_vitrenko [27]
The sales tax is 3.49 I think
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3 years ago
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Kiara desea contratar el servicio de una línea telefónica con internet para realizar sus clases virtuales. Si el costo de una lí
ArbitrLikvidat [17]

a) Kiara ha adquirido una línea de telefonía móvil con internet a un Coste Fijo de 10 soles y un Tasa de Consumo de 1,5 soles por hora consumida.

b) El Coste total por 48 horas de consumo de la línea telefónica con internet es 82 soles.

a) Nota - Puesto que la ecuación que describe el Coste ya existe en el enunciado, entonces se entiende el verbo <em>"Expresa"</em> como <em>"Describa en sus propias palabras"</em>.

Como puede apreciarse el Coste de la línea telefónica móvil aumenta linealmente con el Tiempo de consumo por parte del usuario. En consecuencia, la función de Coste queda definida como sigue:

C(t) = C_{o} + r\cdot t (1)

Donde:

  • C_{o} - Coste fijo, en soles.
  • r - Tasa de consumo, en soles por hora.

Entonces, tenemos que Kiara ha adquirido una línea de telefonía móvil con internet a un Coste Fijo de 10 soles y un Tasa de Consumo de 1,5 soles por hora consumida.

b) Una característica de las Funciones Lineales es que tanto su Dominio como Rango comprenden al Conjunto de todos los Números Reales, al ser de Pendiente constante esta Función.

Por tanto, el Dominio y el Rango de la Función en cuestión es el Conjunto de todos los Números Reales.

c) Si sabemos que C_{o} = 10, r = 1,5 y t = 48, entonces el Coste Total por concepto de 48 horas de consumo es:

C(48) = 10 + 1,5\cdot (48)

C(48) = 82

El Coste total por 48 horas de consumo de la línea telefónica con internet es 82 soles.

Invitamos a ver este problema sobre Costes: brainly.com/question/15723794

7 0
3 years ago
How are exponential functions related to logarithmic functions?<br> Model that with an example.
scoundrel [369]
Exponential functions are related to logarithmic functions in that they are inverse functions. Exponential functions move quickly up towards a [y] infinity, bounded by a vertical asymptote (aka limit), whereas logarithmic functions start quick but then taper out towards an [x] infinity, bounded by a horizontal asymptote (aka limit).
If we use the natural logarithm (ln) as an example, the constant "e" is the base of ln, such that:
ln(x) = y, which is really stating that the base (assumed "e" even though not shown), that:
{e}^{y}  = x
if we try to solve for y in this form it's nearly impossible, that's why we stick with ln(x) = y
but to find the inverse of the form:
{e}^{y}  = x
switch the x and y, then solve for y:
{e}^{x}  = y
So the exponential function is the inverse of the logarithmic one, f(x) = ln x
3 0
3 years ago
Solve for v.<br> 4v = 676
SpyIntel [72]

Answer:

v=169

Step-by-step explanation:

4v=676

Divide by 4.

v=\frac{676}{4}

v=169

6 0
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AfilCa [17]

Answer:

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Step-by-step explanation:

This seems to be a Chihuahua breed of a dog

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