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forsale [732]
2 years ago
15

In the equation below, solve for y: 2x+5y=12

Mathematics
1 answer:
Liula [17]2 years ago
7 0

Answer:

y = \frac{12-2x}{5}

Step-by-step explanation:

Given

2x + 5y = 12

Isolate the term in y by subtracting 2x from both sides

5y = 12 - 2x ( divide both sides by 5 )

y = \frac{12-2x}{5}

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Food and clothing are shipped to victims of a natural disaster. Each carton of food will feed 13 ​people, while each carton of c
lutik1710 [3]

Answer:

  233 cartons of food; 467 cartons of clothing

Step-by-step explanation:

This linear programming problem can be formulated as two inequalities (in addition to the usual constraints that the variables be non-negative). One of these expresses the constraint on weight. Let f and c represent numbers of food and clothing containers, respectively.

  40f +25c ≤ 21000

The other expresses the limit on volume.

  20f + 5c ≤ 7000

_____

<u>Feasible Region vertex</u>

We can subtract the boundary line equation of the first inequality from that of 5 times the second to find f:

  5(20f +5c) -(40f +25c) = 5(7000) -21000

  60f = 14000

  f = 233 1/3

The second boundary line equation can be rearranged to find c:

  c = 1400 -4f = 466 2/3

The nearest integer numbers to these values are ...

  (f, c) = (233, 467)

The other vertices of the feasible region are associated with one or the other variable being zero: (f, c) = (0, 840) or (350, 0).

<u>Check of Integer Solution</u>

Trying these in the constraint inequalities gives ...

  • 40·233 +25·467 = 20,995 < 21000
  • 20·233 +5·467 = 6995 < 7000

<u>Selection of the Answer</u>

The answer to the question will be the feasible region vertex that maximizes the number of people helped. That is, we want to maximize ...

  p = 13f + 6c

The values of p at the vertices are ...

  p = 13·233 + 6·467 = 5831

  p = 13·0 + 6·840 = 5040

  p = 13·350 + 6·0 = 2100

The most people are helped when the plane is filled with 233 food cartons and 467 clothing cartons.

7 0
2 years ago
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