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Bas_tet [7]
4 years ago
14

How do I figure out this problem 3x – 11 < 4 or 4x + 9 ≥ 1

Mathematics
1 answer:
serious [3.7K]4 years ago
8 0
You need to find x for both equations first

3x - 11 < 4 4x + 9 ≥ 1
+ 11. +11. -9. -9

3x < 15 4x ≥ -8
/3. /3 /4. /4

X < 5 X ≥ -2


Then you plug in x in the equations
3(5) - 11 < 4. 4(-2) + 9 ≥ 1
15 - 11 < 4 -8 + 9 ≥ 1
4 < 4 1. ≥ 1

False True
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Can someone answer this for me pls and thank you
kherson [118]

x in terms of b:

-2(bx - 5) = 16

-2bx + 10 = 16

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--------------------------------

when b = 3 then

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Answer

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