All categories

3 years ago

A quadrilateral is a parallelogram only if both pairs of opposite sides are equal.

Mathematics

2 answers:

monitta3 years ago

6 0

Answer:

True

Step-by-step explanation:

A parallelogram is a quadrilateral with 4 sides and both pairs of opposite sides are equal.

damaskus [11]3 years ago

6 0

Answer:

Hey there! The answer to your question will be below.

Step-by-step explanation:

The correct answer would be A. True

Both sides of the opposite sides are equal and has to have 4 sides so a quadrilateral is a parallogram.

A quadrilateral is a parallelogram only if both pairs of opposite sides are equal

= TRUE!

Hope this helps!

By: xBrainly

You might be interested in

HELP NOW ASAP HURRY i don't got all day!!!!!!!!!!!!!

Anarel [89]

Answer:

15 3/4t^2 + 5 1/4

Explanation:

h(t)=-16t^2+400

We can add 400 then - 64 and show as 8^2

= h(t)=-16t^2+400 - 8^2

But we also need to change 16t^2;

We divide 64 into 16 = 16/64 =0.25

and show 16t^2 changes by 0.25 = 1/4

15 3/4t^2 + 400-64

Can now look like

15 3/4t^2 + 5 1/4

As 5 1/4 = 64 x 5 1/4 = 336

8 0

3 years ago

A rectangle is drawn on a coordinate plane. Three vertices of the rectangle are points L(−3,10) , M(6,10) , and P(−3,−6) . Point

vovangra [49]

Hello!
----------
The answer is 16.
----------
Hope this helps and have a great day!

3 0

3 years ago

Read 2 more answers

Find the volume of the solid generated when R (shaded region) is revolved about the given line. x=6−3sec y, x=6, y= π 3, and

Dmitrij [34]

Answer:

$V=9\pi\sqrt{3}$

Step-by-step explanation:

In order to solve this problem we must start by graphing the given function and finding the differential area we will use to set our integral up. (See attached picture).

The formula we will use for this problem is the following:

$V=\int\limits^b_a {\pi r^{2}} \, dy$

where:

$r=6-(6-3 sec(y))$

$r=3 sec(y)$

a=0

$b=\frac{\pi}{3}$

so the volume becomes:

$V=\int\limits^\frac{\pi}{3}_0 {\pi (3 sec(y))^{2}} \, dy$

This can be simplified to:

$V=\int\limits^\frac{\pi}{3}_0 {9\pi sec^{2}(y)} \, dy$

and the integral can be rewritten like this:

$V=9\pi\int\limits^\frac{\pi}{3}_0 {sec^{2}(y)} \, dy$

which is a standard integral so we solve it to:

$V=9\pi[tan y]\limits^\frac{\pi}{3}_0$

so we get:

$V=9\pi[tan \frac{\pi}{3} - tan 0]$

which yields:

$V=9\pi\sqrt{3}$ ]

6 0

3 years ago

Kelli works at a department store that sells shoes. She receives an employee discount for any shoes she buys at the store. If je

Irina-Kira [14]

30% off
your welcome ;D two week old question tho
thats rare

8 0

3 years ago

If a*b means 2a + b , then what is 2*5 ?

NeX [460]

Answer:

Step-by-step explanation:

let a = 2

b = 5

2a + b

Substituting the values,

=> 2(2) + 5

=> 4 + 5

=> 9

3 0

3 years ago