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Maurinko [17]
4 years ago
11

If sin theta = -1/2 and lies in the third quadrant, what is the cos?

Mathematics
1 answer:
never [62]4 years ago
5 0
Sin angle that equals the 1/2 value is the 30 degree on the 1st Quadrant.

The angle of 30 degree on the 3rd Quadrant is equivalent to (formula and circle in the 1st photo) 180 + 30 = 210°.

So theta = 210° (3rd Quadrant) = 30° (1st Quadrant).

cos \: 30\degree = \sqrt{3} \div 2

Now just transfer the cos 30° to the 3rd Quadrant and the signal will be negative (as shown in the 2nd photo attached).

cos \: 210 \degree = - \sqrt{3} \div 2

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Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the temperature is 80 degrees at midnig
Vladimir [108]

Answer:

The equation is given by:

D(t) = 80 + 9\sin{0.2618t}

Step-by-step explanation:

Sine function:

Has the following format:

y = A\sin{bx}

In which A is the amplitude and \frac{2\pi}{b} is the period.

Suppose you know the temperature is 80 degrees at midnight and the high and low temperature during the day are 89 and 71 degrees

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During a 24-hour day, which means that the period is 24. So

\frac{2\pi}{b} = 24

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V(t) = 9\sin{0.2618t}

Assuming t is the number of hours since midnight, find an equation for the temperature, D, in terms of t.

Initial temperature of 80, so:

D(t) = 80 + V(t) = 80 + 9\sin{0.2618t}

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8a – 10 = 6a in words​
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Answer:

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Step-by-step explanation:

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