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Gre4nikov [31]
3 years ago
7

HELP ASAP!! WILL GIVE BRAINLIEST!! ANSWER ALL PLEASE!!

Mathematics
1 answer:
agasfer [191]3 years ago
6 0

Answer:

B) and A)

Step-by-step explanation:

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PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS PLS ASAP
Alenkasestr [34]

Answer:

(0, 6)

explanation:

  • original coordinates of C: (5, -6)

if reflected over x-axis, then use the formula: (x,y) → (x, -y)

  • new coordinates: (5, 6)

then if translated -5 horizontally, there will be change in x axis

  • new coordinates: (5-5, 6) → (0, 6)
3 0
2 years ago
Easy Points if you know math. Please help, question attached in picture.
blagie [28]

Answer:

y = 1/2x +6

Step-by-step explanation:

We have a point and a slope.  Therefore we can use the point slope form to create a line

y-y1 = m(x-x1)

y-5 = 1/2(x--2)

y-5 = 1/2(x+2)

Distribute the 1/2

y-5 = 1/2x +1

Add 5 to each side

y-5+5 = 1/2x +1+5

y = 1/2x +6

This is in slope intercept form

6 0
2 years ago
Write the equation of the sphere in standard form. x^2 + y^2 + z^2 + 2x − 4y − 6z = 22
madam [21]

The equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Given equation of sphere be x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We are required to express the given equation in the standard form of the equation of sphere.

Equation is basically relationship between two or more variables that are expressed in equal to form. Equation of two variables look like ax+by=c. It may be linear equation,quadratic equation, cubic equation or many more depending on the powers of variables. The standard form of the equation of sphere looks like  x^{2} +y^{2} +z^{2} =r^{2}.

The given equation is x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We have to break 22 which is in right side into various parts according to the left side of the equation.

x^{2} +y^{2} +z^{2} +2x-4y-6z=-1-4-9+36

x^{2} +y^{2} +z^{2} +2x-4y-6z+1+4+9=36

x^{2} +1+2x+y^{2}+4-4y+z^{2} +9-6z=36

x^{2} +(1)^{2} +2*1*x+y^{2} +(2)^{2} -2*2y+z^{2} +(3)^{2} -2*3z=36

(x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}

Hence the equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Learn more about equations at brainly.com/question/2972832

#SPJ4

7 0
1 year ago
How do you find the value of x^2 + 8 when x = 5
Ivahew [28]

Answer:

Step-by-step explanation:

when x = 5

x² + 8

= (5)² + 8

= 25 + 8

= 33

8 0
2 years ago
Read 2 more answers
If possible could you explain how to get the answer if not it is ok.
Softa [21]

Rules of exponents come in hand here.

Multiplication rule: a^m x a^n = a^ m+n

Division rule: a^m / a^n = a^m-n

Negative exponent: a^-m = 1/a^m; 1a^-m =a^m

So it would be (-3)^7+5 / (-3)^-2; (-3)^12 / (-3)^-2; (-3)^12 x (-3)^2; (-3)^14

The answer is (-3)^14. If you multiply it out it is 4,782,969.

3 0
2 years ago
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