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forsale [732]
3 years ago
7

Write an equation of a line that passes through the point (1,2) and is parallel to the line y=-5x+4

Mathematics
1 answer:
kkurt [141]3 years ago
7 0
Y=-5x+7. Is the answer
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Which logarithmic equation is equivalent to 2^5=32?
kolbaska11 [484]

Answer: 5=log_{2}(32)


Step-by-step explanation:

1. By definition, you have if y=b^{x}, then x=log_{b}(y)

2. Keeping this on mind, you must follow the proccedure shown below:

- You have that:

2^{5}=32

Where:

x=5\\y=32\\b=2

- Substitute values into x=log_{b}(y). Then, you obtain:

5=log_{2}(32)


6 0
3 years ago
Read 2 more answers
Factor out the greatest common factor. 10a3b−6a2b2
podryga [215]

Answer:

2a^2b(5a-3b)

If not then the other way is

5a-3b

Step-by-step explanation:

The GCF of 10a^3b and -6a^2b^2 is 2a^2b

So divide by that you will get

2a^2b(5a-3b)

4 0
3 years ago
A sandwich store charges a delivery fee to bring lunch to an office building. One office pays $33 for 4 turkey sandwiches. Anoth
shutvik [7]

Answer:

$12

Step-by-step explanation:

assuming that the cost of delivery is constant irrespective of the number ordered

Let the cost of sandwich be x

First office

$33=4x+c where c is the cost of delivery

Second office

$61=8x+c

These two are simultaneous equation. Subtracting the equation of first office from the second office we obtain

4x=28

Therefore, x=28/4=7

The cost of delivery is 33-(4*7)=33-28=5

Therefore, one sandwich plus delivery costs 7+5=$12

5 0
4 years ago
Juanita has a bag of mixed nuts.her bag contains 27 cashews, 45 almonds and 18 peanuts. What is the ratio of cashews to almonds
Afina-wow [57]
Cashews to almonds
27:45
Reduce by dividing by 9:
3:5
8 0
3 years ago
Read 2 more answers
A researcher wishes to estimate the number of households with two cars. How large a sample is needed in order to be 99% confiden
solmaris [256]

Answer:

Sample size n = 1382

so correct option is D) 1382

Step-by-step explanation:

given data

confidence level = 99 %

margin of error = 3%

probability = 25 %

to find out

How large a sample size needed

solution

we know here P = 25 %

so 1 - P = 1 - 0.25

1 - P  = 0.75

and we know E margin of error is 0.03 so value of Z for 99%

α = 1 - 99%   = 1 - 0.99

α  = 0.01

and  \frac{\alpha}{2} = \frac{0.01}{2}

\frac{\alpha}{2}  = 0.005

so Z is here

Z_(\frac{\alpha}{2}) = 2.576

so

sample size will be

Sample size n =  (\frac{(Z_(\frac{\alpha}{2})}{E})^2 * P * (1-P)

put here value

Sample size n = (\frac{2.576}{0.03})^2 * 0.25 * 0.75

Sample size n = 1382

so correct option is D) 1382

3 0
3 years ago
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