All categories

3 years ago

Write an equation of a line that passes through the point (1,2) and is parallel to the line y=-5x+4

Mathematics

1 answer:

kkurt [141]3 years ago

7 0

Y=-5x+7. Is the answer

You might be interested in

Which logarithmic equation is equivalent to 2^5=32?

kolbaska11 [484]

Answer: $5=log_{2}(32)$

Step-by-step explanation:

1. By definition, you have if $y=b^{x}$ , then $x=log_{b}(y)$

2. Keeping this on mind, you must follow the proccedure shown below:

- You have that:

$2^{5}=32$

Where:

$x=5\\y=32\\b=2$

- Substitute values into $x=log_{b}(y)$ . Then, you obtain:

$5=log_{2}(32)$

6 0

3 years ago

Read 2 more answers

Factor out the greatest common factor. 10a3b−6a2b2

podryga [215]

Answer:

2a^2b(5a-3b)

If not then the other way is

5a-3b

Step-by-step explanation:

The GCF of 10a^3b and -6a^2b^2 is 2a^2b

So divide by that you will get

2a^2b(5a-3b)

4 0

3 years ago

A sandwich store charges a delivery fee to bring lunch to an office building. One office pays $33 for 4 turkey sandwiches. Anoth

shutvik [7]

Answer:

$12

Step-by-step explanation:

assuming that the cost of delivery is constant irrespective of the number ordered

Let the cost of sandwich be x

First office

$33=4x+c where c is the cost of delivery

Second office

$61=8x+c

These two are simultaneous equation. Subtracting the equation of first office from the second office we obtain

4x=28

Therefore, x=28/4=7

The cost of delivery is 33-(4*7)=33-28=5

Therefore, one sandwich plus delivery costs 7+5=$12

5 0

4 years ago

Juanita has a bag of mixed nuts.her bag contains 27 cashews, 45 almonds and 18 peanuts. What is the ratio of cashews to almonds

Afina-wow [57]

Cashews to almonds
27:45
Reduce by dividing by 9:
3:5

8 0

3 years ago

Read 2 more answers

A researcher wishes to estimate the number of households with two cars. How large a sample is needed in order to be 99% confiden

solmaris [256]

Answer:

Sample size n = 1382

so correct option is D) 1382

Step-by-step explanation:

given data

confidence level = 99 %

margin of error = 3%

probability = 25 %

to find out

How large a sample size needed

solution

we know here P = 25 %

so 1 - P = 1 - 0.25

1 - P = 0.75

and we know E margin of error is 0.03 so value of Z for 99%

α = 1 - 99% = 1 - 0.99

α = 0.01

and $\frac{\alpha}{2}$ = $\frac{0.01}{2}$

$\frac{\alpha}{2}$ = 0.005

so Z is here

$Z_(\frac{\alpha}{2})$ = 2.576

sample size will be

Sample size n = $(\frac{(Z_(\frac{\alpha}{2})}{E})^2 * P * (1-P)$

put here value

Sample size n = (\frac{2.576}{0.03})^2 * 0.25 * 0.75

Sample size n = 1382

so correct option is D) 1382

3 0

3 years ago