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marusya05 [52]
3 years ago
12

a homeowner plans to hang wallpaper on one wall of a bedroom that is 10 feet long. if a strip of wallpaper is 20 inches wide and

strips are hung vertically, how many strips of wallpaper will the homeowner require?
Mathematics
1 answer:
love history [14]3 years ago
4 0
1 ft = 12 inches....so 10 ft = (10 * 12) = 120 inches

each strip of wall paper is 20 inches...

so 120/20 = 6 strips of wall paper are required <==


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in the unted states, the height of men are normally distributed with the mean 69 inches and standard deviation 2.8 inches. If 16
yaroslaw [1]

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Probability that their mean height is less than 68 inches is 0.0764.

Step-by-step explanation:

We are given that in the united states, the height of men are normally distributed with the mean 69 inches and standard deviation 2.8 inches.

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<em>Let </em>\bar X<em> = sample mean height</em>

The z-score probability distribution for sample mean is given by;

              Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean height = 69 inches

            \sigma = population standard deviation = 2.8 inches

            n = sample of men = 16

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the mean height of 16 randomly selected men is less than 68 inches is given by = P(\bar X < 68 inches)

 P(\bar X < 68 inches) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < \frac{68-69}{\frac{2.8}{\sqrt{16} } } ) = P(Z < -1.43) = 1 - P(Z \leq 1.43)

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<em>Now, in the z table the P(Z  x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 1.43 in the z table which has an area of 0.92364.</em>

Therefore, probability that their mean height is less than 68 inches is 0.0764.

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