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OlgaM077 [116]
3 years ago
13

A nurse is making identical first aid bags for patients using 72 antiseptic wipes, 55 adhesive bandages, and 36 packets of ointm

ent. What is the greatest number of identical first aid bags the nurse can make with the least amount of items leftover? Describe the contents of each bag.
Mathematics
1 answer:
alexandr1967 [171]3 years ago
8 0
<span>To make identical first aid bags and maximize the amount, you first have to take the item that you have the least amount of and make that your base amount of bags with one item per bag. Doing that for the nurse gives 36 bags with 1 packet of ointment per bag and 0 left over. Next, you know that you have 72 antiseptic wipes which is double the amount of ointment, so you would put 2 antiseptic wipes in each bag and have 0 left over. Finally, since 55 bandages is not double 35, you would put one bandage in each bag and have 19 bandages left over. In summary, there would be 36 bags, with each having 2 antiseptic wipes, 1 adhesive bandage, and one packet of ointment. There would be 19 adhesive bandages leftover.</span>
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It would be
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Segment PH is graphed on the coordinate grid where P is (-31,8) and H is (29,-10). Point E is the midpoint of segment PH. If poi
maks197457 [2]

Answer:

The coordinates of point A are (-11 , 2)

Step-by-step explanation:

- The coordinates of point P are (-31 , 8)

- The coordinates of point H are (29 , -10)

- Point E is the mid-point of segment PH

- The coordinates of the the mid-point are:

→ x=\frac{x_{1}+x_{2}}{2} and y=\frac{y_{1}+y_{2}}{2}

∵ E is the mid-point of segment PH

∴ The x-coordinate of point E is x=\frac{-31+29}{2}=-1

∴ The x-coordinate of point E is -1

∴ The y-coordinate of point E is y=\frac{8+-10}{2}=-1

∴ The y-coordinate of point E is -1

∴ The coordinates of point E are (-1 , -1)

- Point A is graphed \frac{2}{3} of the way along the segment from P to E

- That mean the distances from points P to A is 2 parts and from P to E

  is 3 parts, then the distance from A to E is "3 - 2" = 1 part

- So point A divides the line segment PE at ratio 2 : 1 from P

- The coordinates of the division point are:

→ x=\frac{x_{1}m_{2}+x_{2}m_{1}}{m_{1}+m_{2}} and y=\frac{y_{1}m_{2}+y_{2}m_{1}}{m_{1}+m_{2}}

∵ Point A divides PE at ratio 2 : 1

∵ The coordinates of point P are (-31 , 8)

∵ The coordinates of point E are (-1 , -1)

∴ The x-coordinate of point A is x=\frac{(-31)(1)+(-1)(2)}{2+1}= -11

∴ The x-coordinate of point A is -11

∴ The y-coordinate of point A is x=\frac{(8)(1)+(-1)(2)}{2+1}=2

∴ The y-coordinate of point A is 2

∴ The coordinates of point A are (-11 , 2)

* The coordinates of point A are (-11 , 2)

3 0
3 years ago
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kakasveta [241]
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