Aidan has 20 ft of fence with which to build a rectangular dog run. What is the maximum area he can enclose? Enter your answer i

Question

3 years ago

8

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1 answer:

irina1246 [14] · Answer 1 · 2022-05-05T00:30:08+03:00

<h2>Maximum area is 25 m²</h2>

Explanation:

Let L be the length and W be the width.

Aidan has 20 ft of fence with which to build a rectangular dog run.

Fencing = 2L + 2W = 20 ft

L + W = 10

W = 10 - L

We need to find what is the largest area that can be enclosed.

Area = Length x Width

A = LW

A = L x (10-L) = 10 L - L²

For maximum area differential is zero

So we have

dA = 0

10 - 2 L = 0

L = 5 m

W = 10 - 5 = 5 m

Area = 5 x 5 = 25 m²

Maximum area is 25 m²